Perimeter of a Pentagon: Formula 5s, Examples

#Geometry
TL;DR
The perimeter of a pentagon is the total distance around its five sides. For a regular pentagon it is $P = 5s$, where $s$ is one side length; for an irregular pentagon you add all five sides, $P = a + b + c + d + e$. This guide derives both formulas, works six examples, and keeps perimeter cleanly separate from area.
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Bhanzu TeamLast updated on July 27, 202611 min read

What Is the Perimeter of a Pentagon?

The perimeter of a pentagon is the sum of the lengths of its five straight sides - the total distance you would walk tracing its outline once. A pentagon is any closed, five-sided polygon, so its perimeter is simply how far around the edge it is, measured in a length unit such as cm, m, or ft.

There are two cases, and telling them apart is the whole task:

  • Regular pentagon - all five sides are equal, so the perimeter is $P = 5s$, where $s$ is the length of one side.

  • Irregular pentagon - the sides differ, so there is no shortcut; you add each side, $P = a + b + c + d + e$.

Perimeter is a one-dimensional measure (a length), which is why its answer carries plain units like metres, not square metres. That distinction matters later, so hold onto it.

The building where the same wall repeats five times

The world's largest office building is a pentagon whose outer walls trace one repeated number. Each of the five façades of the Pentagon in Arlington runs the same length, so measuring the whole boundary means measuring one side and multiplying by five. That single idea, one side times five, is the entire secret of a regular pentagon's perimeter, and it is what makes this shape one of the friendliest in geometry to measure.

What Are the Properties of a Regular Pentagon?

A regular pentagon - the case where $P = 5s$ applies - carries a small set of fixed properties worth knowing before measuring its boundary:

  • Five equal sides. All five sides share one length $s$, which is exactly why the perimeter collapses to $5s$.

  • Five equal interior angles. Each interior angle measures $108°$, and the five together sum to $540°$.

  • Five equal exterior angles. Each exterior angle is $72°$, since the exterior angles of any polygon sum to $360°$ and $360° \div 5 = 72°$.

  • Five lines of symmetry. A regular pentagon maps onto itself under five reflections and a $72°$ rotation.

  • Five diagonals. Joining non-adjacent vertices gives five diagonals, which trace the familiar pentagram inside.

Only the first property - equal sides - is needed for the perimeter, but the equal-angle and symmetry facts are what mark a pentagon as regular in the first place, and therefore what license the $5s$ shortcut.

Why Is the Regular Pentagon Formula Just 5 Times the Side?

The formula $P = 5s$ is not a rule to memorise blindly; it falls straight out of the definition. Perimeter means "add every side." A regular pentagon has five sides, and regular means they are all the same length $s$. So the sum is

$P = s + s + s + s + s$

Five identical terms added together is exactly what multiplication is shorthand for:

$P = 5 \times s = 5s$

That is the entire derivation. The multiplication form $5s$ and the addition form $s + s + s + s + s$ describe the same thing; the first is just faster. For any regular polygon with $n$ equal sides, the same reasoning gives $P = n \times s$, and the general perimeter formula is always "add the sides." The pentagon is the $n = 5$ case.

How Do You Find the Perimeter of an Irregular Pentagon?

When the five sides are not equal, there is genuinely no formula to shortcut — and that is the point people miss. You measure or read off each of the five side lengths and add them:

$P = a + b + c + d + e$

If a pentagon has sides 10, 8, 12, 9, and 11 metres, its perimeter is $10 + 8 + 12 + 9 + 11 = 50$ metres. Every side must be included exactly once. The only trap is a missing side or a wrong unit, which is why writing all five lengths down first, before adding, is worth the extra line.

How Do You Find the Perimeter of a Pentagon From Its Apothem or Radius?

Sometimes a regular pentagon is described not by its side but by its apothem (the perpendicular distance from the centre to the middle of a side) or its circumradius (the distance from the centre to a vertex). In both cases you first recover the side length $s$, then multiply by five.

From the apothem $a_{\text{p}}$:

$s = 2 \times a_{\text{p}} \times \tan\left(\frac{180°}{5}\right) = 2,a_{\text{p}}\tan 36°, \qquad P = 5s$

From the circumradius $r$:

$s = 2 \times r \times \sin\left(\frac{180°}{5}\right) = 2,r\sin 36°, \qquad P = 5s$

The variables are:

Symbol

Meaning

$P$

Perimeter of the pentagon

$s$

Length of one side

$a_{\text{p}}$

Apothem, the centre-to-mid-side distance

$r$

Circumradius, the centre-to-vertex distance

$36°$

Half the central angle, $\tfrac{180°}{5}$

For example, a regular pentagon with apothem $a_{\text{p}} = 4$ cm has side $s = 2 \times 4 \times \tan 36° \approx 5.81$ cm, so $P = 5 \times 5.81 \approx 29.06$ cm. These formulas are just the side length wearing a trig disguise; the perimeter step is always $5s$.

How Is Perimeter Different From Area of a Pentagon?

Perimeter and area answer two different questions, and mixing them is the single most common error. Perimeter is the distance around the pentagon (a length, in cm or m). Area is the space inside it (in cm² or m²). You cannot find one from the other without more information.

There is one useful bridge for a regular pentagon: its area equals half the perimeter times the apothem - the perpendicular distance from the centre to the middle of a side:

$A = \frac{1}{2} \times P \times a_{\text{p}}$

Here $P$ is the perimeter you already know how to find, and $a_{\text{p}}$ is the apothem. So perimeter is often a stepping stone to area, but the two are never the same number, and they never share a unit.

Examples of Perimeter of a Pentagon

Six examples, from a plain regular pentagon up to working backward from the perimeter and reading a real map.

Example 1

Find the perimeter of a regular pentagon with each side 7 cm.

All five sides are equal, so use $P = 5s$ with $s = 7$.

$P = 5 \times 7 = 35$

Final answer: 35 cm.

Example 2

A student finds the perimeter of a regular pentagon of side 6 m by writing "$P = 5 + 6 = 11$ m." Where does this go wrong?

The tempting move reads "5 sides" and "6 m" and adds the two numbers, giving 11 m. That treats the count of sides as if it were a length.

The 5 in $P = 5s$ is not a side to be added; it counts how many times the side length repeats. Perimeter adds lengths, and there is only one length here - 6 m - occurring five times. The correct method multiplies:

$P = 5 \times s = 5 \times 6 = 30$

Final answer: 30 m. The 5 multiplies the side; it is never added to it.

Example 3

An irregular pentagon has sides 4 cm, 6 cm, 5 cm, 7 cm, and 3 cm. Find its perimeter.

The sides are unequal, so add all five.

$P = 4 + 6 + 5 + 7 + 3$

$P = 25$

Final answer: 25 cm. Notice no side length was left out and none was used twice.

Example 4

The perimeter of a regular pentagon is 45 mm. Find the length of one side.

Here the perimeter is known and the side is the unknown, so run $P = 5s$ backward.

$45 = 5 \times s$

$s = \frac{45}{5} = 9$

Final answer: each side is 9 mm.

Example 5

A regular pentagon has side 8 cm. Find its perimeter, then use an apothem of 5.5 cm to find its area.

First the perimeter:

$P = 5 \times 8 = 40 \text{ cm}$

Now the area, using $A = \tfrac{1}{2} \times P \times a_{\text{p}}$:

$A = \frac{1}{2} \times 40 \times 5.5 = 110$

Final answer: perimeter 40 cm, area 110 cm². Same shape, two different measures, two different units.

Example 6

A pentagon-shaped garden bed has sides measured as 3.5 m, 3.5 m, 4 m, 2 m, and 2 m. A gardener needs edging for the full border. How much edging is required?

"Full border" is the perimeter. The sides are not all equal, so this is the irregular case; add them.

$P = 3.5 + 3.5 + 4 + 2 + 2$

$P = 15$

Final answer: 15 m of edging. The reasoning step is recognising that "border length" is exactly the perimeter.

Where Does Pentagon Perimeter Actually Get Used?

The perimeter of a pentagon is not a textbook curiosity; it is the number you reach for whenever a five-sided boundary has to be measured, fenced, framed, or trimmed.

  • Fencing and edging. A pentagon-shaped plot, pond, or garden bed needs its perimeter to order the right length of fence or border.

  • Framing and trim. Pentagon windows, mirrors, and signs need their perimeter to cut the surrounding frame.

  • Design and packaging. Home plate in baseball is a pentagon; its regulated boundary is a perimeter specification.

The clearest real-world anchor is the Pentagon building itself: five outer walls, each about 921 feet long, giving an outer perimeter of roughly 4,600 feet. Because the building is a regular pentagon, that boundary is one wall length times five - the same $P = 5s$ a student uses on a 7 cm figure, scaled up to a landmark. The formula does not care whether the side is centimetres or the length of a corridor.

What Are the Most Common Mistakes With Pentagon Perimeter?

Three errors account for most wrong answers, and each has a clean fix.

Mistake 1: Adding the number of sides to the side length

Where it slips in: The moment a student sees "5 sides" and a side length and reaches for a single addition.

Don't do this: Writing $P = 5 + s$ (for side 6 m, that gives the meaningless 11 m).

The correct way: In $P = 5s$ the 5 is a count of how many times the length repeats, so it multiplies. Students first meeting the formula almost always want to add the 5, because the shape "has five sides" sounds additive. The fix is to read $5s$ as "five lots of $s$," which is $5 \times s$.

Mistake 2: Using P = 5s on an irregular pentagon

Where it slips in: Applying the tidy regular formula to any five-sided figure without checking the sides are equal.

Don't do this: Multiplying one side by 5 when the five sides clearly differ.

The correct way: $P = 5s$ is only for regular pentagons, where all sides are equal. The rusher who grabs the shortcut every time lands here. Check first: equal sides means $5s$; unequal sides means add all five, $a + b + c + d + e$.

Mistake 3: Confusing perimeter with area

Where it slips in: Being asked for the distance around and instead computing the space inside (or vice versa), and reporting the wrong unit.

Don't do this: Answering a "how much fencing" question in square metres.

The correct way: Perimeter is a length (cm, m) and area is a coverage (cm², m²). A quick unit check catches this every time.

Conclusion

  • The perimeter of a pentagon is the total distance around its five sides.

  • For a regular pentagon, $P = 5s$ — one side length multiplied by five.

  • For an irregular pentagon, add all five sides: $P = a + b + c + d + e$.

  • Perimeter is a length; it is never the same as area and never uses square units.

To take pentagon perimeter further with a teacher, explore Bhanzu's geometry tutor, a middle school math tutor, or structured math classes online.

Practice These to Solidify Your Understanding

Work through these, then check your answers:

  1. Find the perimeter of a regular pentagon with side 12 cm. (Answer to Question 1: 60 cm.)

  2. An irregular pentagon has sides 5, 9, 6, 8, and 7 m. Find its perimeter. (Answer to Question 2: 35 m.)

  3. The perimeter of a regular pentagon is 65 mm. Find one side. (Answer to Question 3: 13 mm.)

If Question 1 tripped you, revisit Example 2 and the multiply-don't-add point. Want a trainer to walk a five-sided figure through with your child? Book a free demo class.

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Frequently Asked Questions

What is the formula for the perimeter of a pentagon?
For a regular pentagon it is $P = 5s$, where $s$ is one side length. For an irregular pentagon there is no shortcut — add the five sides, $P = a + b + c + d + e$.
How many sides does a pentagon have?
Exactly five. That is why the regular-pentagon perimeter multiplies the side by five.
Can you find the perimeter of a pentagon from its area?
Not directly. Area and perimeter measure different things. For a regular pentagon you can link them through the apothem with $A = \tfrac{1}{2} \times P \times a_{\text{p}}$, but you need at least one more measurement.
Is the perimeter of a pentagon measured in square units?
No. Perimeter is a length, so it uses plain units (cm, m, ft). Square units (cm², m²) belong to area.
What is the perimeter of a regular pentagon with side 10 cm?
$P = 5 \times 10 = 50$ cm.
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Bhanzu’s editorial team, known as Team Bhanzu, is made up of experienced educators, curriculum experts, content strategists, and fact-checkers dedicated to making math simple and engaging for learners worldwide. Every article and resource is carefully researched, thoughtfully structured, and rigorously reviewed to ensure accuracy, clarity, and real-world relevance. We understand that building strong math foundations can raise questions for students and parents alike. That’s why Team Bhanzu focuses on delivering practical insights, concept-driven explanations, and trustworthy guidance-empowering learners to develop confidence, speed, and a lifelong love for mathematics.
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