Square Root of 93 - How to Find the Square Root of 93?

#Algebra
TL;DR
The square root of 93 ($\sqrt{93}$) is about $9.6437$. This article gives the exact radical form, the decimal to four places, the long division method for computing it by hand, why $\sqrt{93}$ is irrational, and where the value shows up in geometry.
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Bhanzu TeamLast updated on August 17, 20266 min read

What Is A Square Root?

The square root of a number $n$ is the value $r$ for which $r^2 = n$. So the square root of 93 is the number that, multiplied by itself, gives 93.

No whole number does that. $9^2 = 81$ is too small, and $10^2 = 100$ is too big, so $\sqrt{93}$ falls between 9 and 10. Every positive number has two square roots, one positive and one negative, but the symbol $\sqrt{93}$ always means the positive, or principal, root.

Where Does √93 Appear?

$\sqrt{93}$ is the space diagonal of a rectangular box with edges 2, 5, and 8. The 3D version of the Pythagorean theorem gives the diagonal as $\sqrt{2^2 + 5^2 + 8^2} = \sqrt{4 + 25 + 64} = \sqrt{93}$. Because 93 sits between the perfect squares $81 = 9^2$ and $100 = 10^2$, the value lands between 9 and 10, closer to 10. Anywhere a length is built from squared parts that total 93, this irrational number is the exact answer.

Quick Reference Table

Number $n$

$\sqrt{n}$ (approx.)

Rational or Irrational

81

9

Rational

85

9.2195

Irrational

90

9.4868

Irrational

93

9.6437

Irrational

96

9.7980

Irrational

100

10

Rational

121

11

Rational

Is The Square Root Of 93 Rational Or Irrational?

$\sqrt{93}$ is an irrational number. It cannot be written as a fraction $\frac{p}{q}$ of two integers, and its decimal runs on forever without repeating.

The quick reason comes from the factors. A whole number has a rational square root only when it is a perfect square. Writing 93 as a product of primes gives:

$$93 = 3 \times 31$$

Both 3 and 31 appear to the first power, so there is no repeated prime to pull out as a pair, and 93 is not a perfect square. That forces $\sqrt{93}$ to be irrational. The same style of argument shows every non-perfect-square whole number has an irrational root, the way you can prove that root 3 is irrational or prove that root 7 is irrational by contradiction.

How Do You Find √93? (Long Division Method)

Prime factorization tells you $\sqrt{93}$ cannot be simplified, but it does not give the decimal. For that, use long division. Here is the method, one step per line.

Step 1: Write 93 as $\overline{93}.\overline{00},\overline{00},\overline{00}$, pairing digits from the decimal point.

Step 2: Find the largest number whose square is at most 93. $9^2 = 81 \leq 93$ Write 9 as the first digit of the answer.

Step 3: Subtract, then bring down the next pair. $93 - 81 = 12$ Bring down $00$ to get $1200$.

Step 4: Double the current answer, 9, to get 18. Find a digit $d$ with $(180 + d) \times d \leq 1200$. $186 \times 6 = 1116 \leq 1200$ The answer is now $9.6$.

Step 5: Subtract and bring down again. $1200 - 1116 = 84$ Bring down $00$ to get $8400$.

Step 6: Double 96 to get 192. Find $d$ with $(1920 + d) \times d \leq 8400$. $1924 \times 4 = 7696 \leq 8400$ The answer is now $9.64$.

Step 7: Continue once more. $8400 - 7696 = 704$ Bring down $00$ to get $70400$ $19283 \times 3 = 57849 \leq 70400$ The answer is now $9.643$.

Carrying the process one more place gives $\sqrt{93} \approx 9.6437$. The division never ends, which is exactly what an irrational value looks like on paper.

Examples Of √93

Example 1

Estimate $\sqrt{93}$ to the nearest whole number.

$9^2 = 81$ $10^2 = 100$ 93 is between 81 and 100, so the root is between 9 and 10. Since 93 is closer to 100, round up. Final answer: 10.

Example 2

A student simplifies $\sqrt{93}$ as $\sqrt{9} \times \sqrt{10.33}$ and stops. What went wrong?

The wrong path first. Splitting 93 as $9 \times 10.33$ does give $\sqrt{9} \times \sqrt{10.33} = 3\sqrt{10.33}$, but $10.33$ is not a whole number, so nothing was actually simplified. To simplify a radical you factor out a perfect square that divides the number evenly. $93 = 3 \times 31$ Neither factor is a perfect square, and no perfect square other than 1 divides 93. Final answer: $\sqrt{93}$ is already in simplest form.

Example 3

Evaluate $(\sqrt{93})^2$.

By definition, squaring undoes a square root. $(\sqrt{93})^2 = 93$ Final answer: 93.

Example 4

Find the value of $2\sqrt{93}$ to two decimal places.

$\sqrt{93} \approx 9.6437$ $2 \times 9.6437 = 19.2874$ Round to two places. Final answer: $19.29$.

Example 5

A cube-shaped tank has a space diagonal of $\sqrt{93}$ metres from combined edges 2, 5, and 8. Confirm the diagonal.

$2^2 + 5^2 + 8^2 = 4 + 25 + 64$ $= 93$ $\text{diagonal} = \sqrt{93} \approx 9.64 \text{ m}$ Final answer: about $9.64$ metres.

Common Mistakes

Mistake 1: Treating 93 as though it could be simplified

Where it slips in: A learner assumes every radical breaks down into something smaller.

Don't do this: Writing $\sqrt{93} = \sqrt{3} \times \sqrt{31}$ and calling it simpler.

The correct way: That split is valid but not simpler, since neither 3 nor 31 is a perfect square. Most students who reach for a factor pair forget to check that one factor is a perfect square. $\sqrt{93}$ stays $\sqrt{93}$.

Mistake 2: Rounding too early

Where it slips in: Multi-step problems where $\sqrt{93}$ appears in the middle.

Don't do this: Replacing $\sqrt{93}$ with $9.64$ at the start and carrying that value through every later step.

The correct way: Keep $\sqrt{93}$ in radical form until the final step, then round once. Early rounding compounds error across multiplications.

Mistake 3: Forgetting the negative root when solving an equation

Where it slips in: Solving $x^2 = 93$.

Don't do this: Writing only $x = \sqrt{93}$.

The correct way: The equation $x^2 = 93$ has two solutions, $x = \sqrt{93}$ and $x = -\sqrt{93}$, written together as $x = \pm\sqrt{93}$. The bare symbol $\sqrt{93}$ still means the positive root alone.

Conclusion

The square root of 93 is an irrational number, about $9.6437$, and $\sqrt{93}$ is already its simplest form because $93 = 3 \times 31$ carries no perfect-square factor. Long division gives the decimal to any precision you need, while prime factorization confirms the radical will not reduce. To take radicals further with a teacher, explore Bhanzu's algebra tutor sessions or structured math classes online. You can also book a free demo class to see the approach in action.

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Frequently Asked Questions

What is the value of $\sqrt{93}$?
$\sqrt{93} \approx 9.6437$. To seven places it is $9.6436508$, and the decimal never terminates because 93 is not a perfect square.
Is 93 a perfect square?
No. The nearest perfect squares are $81 = 9^2$ and $100 = 10^2$, and 93 sits between them.
What is $\sqrt{93}$ in simplest radical form?
$\sqrt{93}$. Since $93 = 3 \times 31$ has no repeated prime factor, there is nothing to take outside the radical.
Between which two whole numbers does $\sqrt{93}$ lie?
Between 9 and 10, and closer to 10.
What is $\sqrt{9.3}$ if $\sqrt{93} \approx 9.6437$?
Divide by $\sqrt{10}$: $\sqrt{9.3} = \frac{\sqrt{93}}{\sqrt{10}} \approx \frac{9.6437}{3.1623} \approx 3.0496$.
✍️ Written By
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