The cube root of 25 is approximately 2.924.
Quick Answer:
Result: $\sqrt[3]{25} \approx 2.924$
Notation: radical form $\sqrt[3]{25}$; exponent form $25^{1/3}$
Method shown: prime factorisation (to test for a cube factor) + estimation between consecutive cubes
Approximate value (irrational): $2.92402$ (to 5 decimal places)
Exact form: $\sqrt[3]{25}$, it does not reduce to a whole number or a simpler radical
Quick Reference Table
The table below places $\sqrt[3]{25}$ among nearby cube roots so you can see where it sits.
Number $n$ | Cube root $\sqrt[3]{n}$ | Exact or approximate |
|---|---|---|
8 | $2$ | Exact (perfect cube) |
24 | $\approx 2.884$ | Irrational |
25 | $\approx 2.924$ | Irrational |
27 | $3$ | Exact (perfect cube) |
64 | $4$ | Exact (perfect cube) |
100 | $\approx 4.642$ | Irrational |
125 | $5$ | Exact (perfect cube) |
Where the Cube Root of 25 Appears
The cube root of 25 shows up whenever a cube's volume is known and you want its edge: a cube holding $25$ cubic units has an edge of $\sqrt[3]{25} \approx 2.924$ units. It also appears in scaling problems, where doubling a linear size multiplies volume by $8$, so working backwards from a volume of $25$ needs a cube root.
What Is a Cube Root?
The cube root of a number $n$ is the value that, multiplied by itself three times, returns $n$. In symbols, $\sqrt[3]{n} = x$ means $x^3 = n$.
The small $3$ tucked into the radical sign is the index, it is what separates a cube root $\sqrt[3]{\phantom{n}}$ from a square root $\sqrt{\phantom{n}}$. For 25, we want the $x$ with $x^3 = 25$.
How to Find the Cube Root of 25
Two methods are worth showing: a prime-factorisation test that tells you whether the answer simplifies, and an estimation that pins down the decimal.
Method 1: Prime factorisation (the simplify test)
Break 25 into primes: $$25 = 5 \times 5 = 5^2$$
A cube root simplifies only when a prime appears three times (or a multiple of three).
Here $5$ appears twice, not three times.
So no factor comes out of the radical.
Final answer: $\sqrt[3]{25}$ stays as $\sqrt[3]{25}$, it cannot be reduced.
Method 2: Estimation between consecutive cubes
Find the perfect cubes on either side of 25: $$2^3 = 8 \qquad 3^3 = 27$$
Since $8 < 25 < 27$, the answer sits between $2$ and $3$, very close to $3$.
Test $2.9$: $2.9^3 = 24.389$.
Test $2.93$: $2.93^3 \approx 25.154$.
The value is between $2.9$ and $2.93$, and refining gives $\approx 2.924$.
Final answer: $\sqrt[3]{25} \approx 2.924$.
Common Mistakes With Cube Root of 25
Mistake 1: Treating 25 like a perfect cube
Where it slips in: 25 is a perfect square ($5^2$), so it is easy to assume it behaves the same way under a cube root.
Don't do this: write $\sqrt[3]{25} = 5$ by borrowing the square-root fact $\sqrt{25} = 5$.
The correct way: check $5^3 = 125$, not 25. The first instinct here is to reuse the square-root value; the cube root of 25 is $\approx 2.924$, nowhere near 5.
Mistake 2: Dropping the index on the radical
Where it slips in: writing the answer quickly.
Don't do this: write $\sqrt{25}$ when you mean the cube root.
The correct way: always show the index, $\sqrt[3]{25}$. Without the small $3$, the symbol reads as a square root, which equals a different value entirely.
Mistake 3: Rounding too early
Where it slips in: using $\sqrt[3]{25}$ inside a longer calculation.
Don't do this: round to $2.9$ at the start and carry that through.
The correct way: keep $\sqrt[3]{25}$ in exact form as long as possible, then round only the final result.
Conclusion
The cube root of 25 is $\sqrt[3]{25} \approx 2.924$, correct to three decimal places.
It is irrational because $25 = 5^2$ has no factor repeated three times, so nothing comes out of the radical.
You can bracket it between $2^3 = 8$ and $3^3 = 27$ to see it lands near 3.
Always keep the index $\sqrt[3]{\phantom{n}}$ visible so it is not misread as a square root.
To build this skill with a teacher, explore Bhanzu's algebra tutor or online math classes.
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