Cube Root of 24 — Value and Simplification Steps

#Algebra
TL;DR
The cube root of 24 simplifies to $\sqrt[3]{24} = 2\sqrt[3]{3}$, with a decimal value of about $2.884$. This article shows the prime-factorization simplification, the estimation method, where it appears, common mistakes, and worked examples.
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Bhanzu TeamLast updated on July 18, 20264 min read

The cube root of 24 is not a whole number, but it does simplify neatly to $2\sqrt[3]{3}$.

Quick Answer:

Result: $\sqrt[3]{24} = 2\sqrt[3]{3} \approx 2.884$

Notation: $\sqrt[3]{24}$ or $24^{1/3}$

Method shown: prime factorization

Approximate value: $2.884$ (to 3 decimal places, irrational)

Exact form: $2\sqrt[3]{3}$

Quick Reference Table

Number

Simplified cube root

Decimal (3 dp)

$\sqrt[3]{8}$

$2$

$2.000$

$\sqrt[3]{16}$

$2\sqrt[3]{2}$

$2.520$

$\sqrt[3]{24}$

$2\sqrt[3]{3}$

$2.884$

$\sqrt[3]{27}$

$3$

$3.000$

$\sqrt[3]{54}$

$3\sqrt[3]{2}$

$3.780$

$\sqrt[3]{64}$

$4$

$4.000$

Where the Cube Root of 24 Appears

The cube root of 24 turns up whenever a volume is known and an edge length is wanted. If a cube-shaped tank holds 24 cubic units, each edge measures $\sqrt[3]{24} \approx 2.884$ units. The same simplification pattern — pulling a perfect-cube factor out from under the radical — is exactly what scientific and engineering calculators do internally before rounding.

What Is the Cube Root of 24?

The cube root of a number is the value that, multiplied by itself three times, returns that number. Since 24 is not a perfect cube — it sits between $2^3 = 8$ and $3^3 = 27$ — its cube root is an irrational number that never terminates.

But it is not fully "stuck" under the radical. Because 24 contains the perfect-cube factor 8, part of it can come out, leaving the simplified form $2\sqrt[3]{3}$. This is the same skill used across cube numbers and radicals.

How to Simplify the Cube Root of 24 (Methods)

Method 1: Prime factorization

Break 24 into its prime factors.

$$24 = 2 \times 2 \times 2 \times 3$$ $$24 = 2^3 \times 3$$

Write the cube root over the factored form.

$$\sqrt[3]{24} = \sqrt[3]{2^3 \times 3}$$

The cube root of $2^3$ is 2, so 2 comes out of the radical while the 3 stays inside.

$$\sqrt[3]{24} = 2\sqrt[3]{3}$$

Final answer: $\sqrt[3]{24} = 2\sqrt[3]{3}$.

Method 2: Estimation for the decimal value

Locate 24 between neighbouring perfect cubes.

$$2^3 = 8$$ $$3^3 = 27$$

So $\sqrt[3]{24}$ lies between 2 and 3, and close to 3 because 24 is close to 27. Testing $2.9$:

$$2.9^3 = 24.389$$

That is slightly above 24, so the answer is a touch below 2.9. Testing $2.88$:

$$2.88^3 \approx 23.888$$

Final answer: $\sqrt[3]{24} \approx 2.884$ to three decimal places.

Common Mistakes With Cube Root of 24

Mistake 1: Dropping the cube-root index

Where it slips in: writing the radical quickly.

Don't do this: writing $\sqrt{24}$ when you mean the cube root.

The correct way: always show the index: $\sqrt[3]{24}$. Without the little 3 it reads as a square root, giving $\approx 4.899$ instead of $\approx 2.884$.

Mistake 2: Pulling out the wrong factor

Where it slips in: simplifying by removing any factor instead of a perfect-cube factor.

Don't do this: writing $\sqrt[3]{24} = 4\sqrt[3]{6}$ by splitting off 4.

The correct way: only a perfect cube factor can leave the radical. Here that is $2^3 = 8$, giving $2\sqrt[3]{3}$.

Mistake 3: Treating the cube root like a square root when simplifying

Where it slips in: grouping factors in pairs instead of triples.

Don't do this: taking one factor out for every pair of 2's.

The correct way: a cube root removes a factor for every three copies. Three 2's give one 2 outside; the leftover 3 has no triple, so it stays inside.

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Frequently Asked Questions

What is the cube root of 24 in simplest radical form?
It is $2\sqrt[3]{3}$, found by pulling the perfect-cube factor $2^3 = 8$ out of 24.
Is the cube root of 24 rational or irrational?
Irrational. Since 24 is not a perfect cube, $\sqrt[3]{24}$ is a non-terminating, non-repeating decimal, about $2.884$.
What is the cube root of 24 as a decimal?
Approximately $2.884$ to three decimal places.
Why does 2 come out of $\sqrt[3]{24}$ but 3 does not?
Because $24 = 2^3 \times 3$. The factor $2^3$ is a perfect cube, so its cube root is the whole number 2; the lone 3 has no cube factor, so it remains under the radical.
How is the cube root of 24 different from the cube root of 27?
$\sqrt[3]{27} = 3$ exactly, because 27 is a perfect cube. $\sqrt[3]{24}$ is irrational and simplifies only to $2\sqrt[3]{3}$.
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