Cube Root of 100 — Value and Steps

#Algebra
TL;DR
The cube root of 100 is an irrational number equal to ∛100 ≈ 4.642, because 100 factors as 2² × 5² with no perfect cube inside it. This article gives the value, the reason ∛100 cannot be simplified, two ways to compute it by hand, and the mistakes to avoid.
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Bhanzu TeamLast updated on July 19, 20265 min read

The cube root of 100 is approximately 4.642. Written exactly it stays as ∛100, since 100 has no perfect-cube factor to pull out, so the decimal never terminates and never repeats.

Quick Answer:

Result: ∛100 ≈ 4.642

Notation: Radical form ∛100; decimal form 4.6416 (to 4 dp)

Method shown: Prime factorisation to test for cube factors, then estimation by bracketing

Approximate value: 4.6416 (irrational, non-terminating)

Exact form: ∛100 (cannot be simplified to a whole number or a smaller radical)

Quick Reference Table of Nearby Cube Roots

The table below sits ∛100 among its neighbours so you can see the spacing between cube roots and check the estimate.

Number $n$

Cube root $\sqrt[3]{n}$

Type

64

$\sqrt[3]{64} = 4$

Exact (perfect cube)

100

$\sqrt[3]{100} \approx 4.642$

Irrational

125

$\sqrt[3]{125} = 5$

Exact (perfect cube)

200

$\sqrt[3]{200} \approx 5.848$

Irrational

216

$\sqrt[3]{216} = 6$

Exact (perfect cube)

1000

$\sqrt[3]{1000} = 10$

Exact (perfect cube)

The two perfect cubes on either side of 100 are 64 and 125, so ∛100 must land between 4 and 5, closer to 5.

What a Cube Root Means

The cube root of a number $n$ is the value that, multiplied by itself three times, gives $n$. In symbols, $\sqrt[3]{n} = x$ means $x^3 = n$. The small 3 tucked into the radical sign is the index; it is what separates a cube root from a square root, and it must always be written for a cube root.

Because $4^3 = 64$ and $5^3 = 125$, and 100 sits between them, ∛100 is a number between 4 and 5 that is not a whole number. That makes it irrational — its decimal expansion runs forever without repeating.

How to Compute the Cube Root of 100

Method 1: Prime factorisation (the simplify test)

Break 100 into primes to check for a perfect-cube factor.

$100 = 2 \times 2 \times 5 \times 5$

$100 = 2^2 \times 5^2$

A cube root simplifies only when a prime appears three times (or in a multiple of three). Here the 2 appears twice and the 5 appears twice — no prime reaches a group of three.

Final answer: ∛100 has no perfect-cube factor, so it cannot be simplified. It stays as $\sqrt[3]{100}$.

Method 2: Estimation by bracketing

Trap the value between two cubes you know, then narrow it.

$4^3 = 64$

$5^3 = 125$

So $4 < \sqrt[3]{100} < 5$. Now test a value in between.

$4.6^3 = 97.336$

$4.7^3 = 103.823$

Since 100 sits between 97.336 and 103.823, the answer is between 4.6 and 4.7, and nearer 4.6.

$4.64^3 = 99.897$

$4.65^3 = 100.545$

Final answer: $\sqrt[3]{100} \approx 4.642$.

Common Mistakes With Cube Root of 100

Mistake 1: Confusing the cube root with the square root

Where it slips in: reading ∛100 as √100 and answering 10.

Don't do this: write $\sqrt[3]{100} = 10$ because $10^2 = 100$.

The correct way: the index is 3, so you need $x^3 = 100$, not $x^2 = 100$. The answer is about 4.642, not 10. Students first meeting radicals often ignore the little index and default to square roots — always read the index first.

Mistake 2: Dropping the index when writing the answer

Where it slips in: copying the radical as a plain √ during a longer calculation.

Don't do this: write $\sqrt{100}$ when you mean the cube root.

The correct way: keep the index visible: $\sqrt[3]{100}$. A missing index silently changes the problem into a square root.

Mistake 3: Trying to force a simplification that isn't there

Where it slips in: assuming every radical breaks into a smaller radical.

Don't do this: claim $\sqrt[3]{100} = 2\sqrt[3]{25}$ by pulling a 2 out.

The correct way: you can only pull out a factor that is itself a perfect cube. Since $100 = 2^2 \times 5^2$ has no cube factor, nothing comes out. $\sqrt[3]{100}$ is already in simplest form.

Conclusion

  • The cube root of 100 is irrational, with value $\sqrt[3]{100} \approx 4.642$.

  • 100 factors as $2^2 \times 5^2$, so it has no perfect-cube factor and ∛100 cannot be simplified.

  • The value sits between 4 and 5 because 100 lies between the cubes 64 and 125.

  • Bracketing between known cubes gives a reliable hand estimate without a calculator.

To go further with radicals and roots alongside a teacher, explore Bhanzu's algebra tutor or browse math classes online.

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Frequently Asked Questions

Is the cube root of 100 rational or irrational?
Irrational. 100 is not a perfect cube, so ∛100 cannot be written as a fraction and its decimal never ends.
What is the cube root of 100 to two decimal places?
About 4.64.
Can ∛100 be simplified into a smaller radical?
No. Its prime factorisation is $2^2 \times 5^2$, and no prime appears three times, so there is no perfect-cube factor to remove.
What is the difference between ∛100 and √100?
$\sqrt{100} = 10$ because $10^2 = 100$, while $\sqrt[3]{100} \approx 4.642$ because that value cubed gives 100. The index changes the answer completely.
What two whole numbers is the cube root of 100 between?
Between 4 and 5, since $4^3 = 64$ and $5^3 = 125$.
✍️ Written By
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Bhanzu Team
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