Sin 50 Degrees : Value 0.7660 and How to Find It

#Trigonometry
TL;DR
The value of sin 50 degrees is about $0.7660$; unlike $45^\circ$ or $60^\circ$, it has no simple radical form, so it is a calculator value. This article gives the decimal, the radian form $\frac{5\pi}{18}$, the cofunction link to $\cos 40^\circ$, why the small-angle shortcut fails here, and worked examples.
BT
Bhanzu TeamLast updated on August 14, 20266 min read

What Does Sin 50 Degrees Mean?

Sine is one of the three trigonometric ratios: in a right triangle it is the side opposite the angle divided by the hypotenuse. So $\sin 50^\circ$ is the fraction of the hypotenuse taken by the opposite side when one angle is $50^\circ$.

On the unit circle, sine is the $y$-coordinate where the rotated radius meets the circle. At $50^\circ$ the radius is more than halfway up toward vertical, landing near $(0.6428, 0.7660)$, so the sine is $0.7660$.

Where Does Sin 50 Degrees Show Up?

Mid-range angles run through surveying, ramps, and structural design, where a support or a line of sight sits well off the horizontal. At $50^\circ$, $\sin 50^\circ \approx 0.766$ means the vertical component is about three-quarters of the length, which shapes the height of a leaning strut or the rise of a steep staircase.

The value also appears in the applications of trigonometry to heights and distances, where an angle of elevation near $50^\circ$ turns a measured distance into a height. It is read as the $y$-coordinate on the unit circle.

Standard-Angle Reference Table

The special first-quadrant angles have exact sine values worth memorising. Fifty degrees is not one of them, so it sits between $45^\circ$ and $60^\circ$ as a decimal only.

Angle (degrees)

Angle (radians)

$\sin\theta$ (exact)

$\sin\theta$ (decimal)

$30^\circ$

$\dfrac{\pi}{6}$

$\dfrac{1}{2}$

$0.5000$

$45^\circ$

$\dfrac{\pi}{4}$

$\dfrac{\sqrt{2}}{2}$

$0.7071$

$50^\circ$

$\dfrac{5\pi}{18}$

no simple radical

$0.7660$

$60^\circ$

$\dfrac{\pi}{3}$

$\dfrac{\sqrt{3}}{2}$

$0.8660$

$90^\circ$

$\dfrac{\pi}{2}$

$1$

$1.0000$

Since $50^\circ$ is not built from a $30$-$60$-$90$ or $45$-$45$-$90$ triangle, it has no tidy exact form; treat it as an approximation skill, not a memorisation target. The table does give a useful check: $\sin 50^\circ$ must land between $\sin 45^\circ$ and $\sin 60^\circ$, which it does. The nearby sin 47° behaves the same way.

How Do You Find The Value Of Sin 50 Degrees?

Because $50^\circ$ is not a special angle, you approximate it rather than derive a radical. Here are three routes.

Method 1: Calculator (degree mode).

Set the calculator to degrees and enter $\sin(50)$, which returns $0.76604444\ldots$. Rounded, $\sin 50^\circ \approx 0.7660$.

Method 2: The cofunction link.

Sine and cosine are cofunctions: $\sin\theta = \cos(90^\circ - \theta)$. So $\sin 50^\circ = \cos 40^\circ$, a fact from the cofunction identities that lets a cosine table return the same value.

Method 3: Bracket between known angles.

The reference table shows $\sin 45^\circ = 0.7071$ and $\sin 60^\circ = 0.8660$. Because $50^\circ$ sits between them and closer to $45^\circ$, the value must land a little above $0.7071$; the calculator confirms $0.7660$. Note that the small-angle shortcut $\sin\theta \approx \theta$ does not apply here: in radians, $50^\circ = \frac{5\pi}{18} \approx 0.8727$, which is far from the true $0.7660$, because the shortcut only holds for angles under roughly $10^\circ$ to $15^\circ$.

Examples Of Sin 50 Degrees

Example 1

Evaluate $10\sin 50^\circ$, rounded to three decimals.

$$10\sin 50^\circ = 10 \times 0.766044 = 7.66044 \approx 7.660$$

Example 2

Estimate $\sin 50^\circ$ with the small-angle rule. A student writes $\sin 50^\circ \approx 0.8727$.

Wrong attempt. The student converts to radians, $50^\circ = \frac{5\pi}{18} \approx 0.8727$, then uses $\sin\theta \approx \theta$ to get $0.8727$.

That overshoots badly: the true value is $0.7660$, an error of more than $14%$. The shortcut is only valid for small angles, and $50^\circ$ is not small.

Correct. For a mid-range angle, use the calculator or the cofunction: $\sin 50^\circ = \cos 40^\circ \approx 0.7660$. Reserve $\sin\theta \approx \theta$ for angles under about $15^\circ$.

Example 3

Find $\dfrac{\sin 50^\circ}{\cos 40^\circ}$.

Because $\sin 50^\circ = \cos 40^\circ$, the ratio is:

$$\frac{\sin 50^\circ}{\cos 40^\circ} = \frac{0.766044}{0.766044} = 1$$

Example 4

A ladder $6$ m long leans against a wall at $50^\circ$ to the ground. Find how high up the wall it reaches.

$$\text{height} = 6 \times \sin 50^\circ = 6 \times 0.766044 \approx 4.596 \text{ m}$$

Example 5

Verify that $\sin 50^\circ = \sin 130^\circ$ using the supplement rule $\sin(180^\circ - \theta) = \sin\theta$.

Since $130^\circ = 180^\circ - 50^\circ$, the rule gives $\sin 130^\circ = \sin 50^\circ \approx 0.7660$. Supplementary angles share the same sine, which is why a second-quadrant $130^\circ$ matches this first-quadrant value.

Where Students Trip Up On Sin 50 Degrees

Mistake 1: Misusing the small-angle approximation

Where it slips in: Applying $\sin\theta \approx \theta$ (radians) to an angle that is not small.

Don't do this: Writing $\sin 50^\circ \approx 0.8727$ from the radian measure.

The correct way: Use the calculator or $\cos 40^\circ$ to get $0.7660$. The learner who applies the small-angle rule everywhere is the one who overshoots on mid-range angles; keep it below about $15^\circ$.

Mistake 2: Expecting a clean radical form

Where it slips in: Assuming every angle simplifies to something like $\frac{\sqrt{3}}{2}$.

Don't do this: Reporting a made-up "simplified" surd for $\sin 50^\circ$.

The correct way: State $\sin 50^\circ \approx 0.7660$ as a decimal, or leave it as $\sin 50^\circ$. Only special-triangle angles have tidy exact forms.

Mistake 3: Confusing sin 50° with sin 5°

Where it slips in: Misreading the angle and dropping or adding a zero.

Don't do this: Writing $\sin 50^\circ \approx 0.0872$, which is actually $\sin 5^\circ$.

The correct way: Check the size: $50^\circ$ is well up the first quadrant, so its sine is large ($0.7660$), while sin 5° is tiny ($0.0872$). A quick bracket against $\sin 45^\circ$ catches this.

Key Takeaways

  • Sin 50 degrees is about $0.7660$; it has no simple radical form because $50^\circ$ is not a special angle.

  • In radians $50^\circ = \frac{5\pi}{18}$, and the value must sit between $\sin 45^\circ$ and $\sin 60^\circ$, which it does.

  • The small-angle approximation fails here; it is reliable only below roughly $10^\circ$ to $15^\circ$.

  • By the cofunction rule $\sin 50^\circ = \cos 40^\circ$, and by the supplement rule $\sin 50^\circ = \sin 130^\circ$.

To build confidence with angles of elevation and estimation, explore Bhanzu's trigonometry tutor or high school math tutor, or browse math classes online.

Practice These Before Moving On

  1. Evaluate $4\sin 50^\circ - 1$, rounded to three decimals.

  2. Use $\sin 50^\circ = \cos 40^\circ$ to rewrite $\sin 50^\circ - \cos 50^\circ$ in terms of cosines.

  3. A kite string $30$ m long makes a $50^\circ$ angle of elevation. Find the kite's height using $\sin 50^\circ$.

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Frequently Asked Questions

What is the exact value of sin 50 degrees?
There is no simple exact value. $50^\circ$ is not a special angle, so it is written as the decimal $0.7660$ or left as $\sin 50^\circ$.
What is sin 50 degrees in radians?
$50^\circ$ equals $\frac{5\pi}{18}$ radians, about $0.872665$, and $\sin\frac{5\pi}{18} \approx 0.7660$.
Is sin 50 degrees equal to cos 40 degrees?
Yes. Sine and cosine are cofunctions, so $\sin 50^\circ = \cos 40^\circ \approx 0.7660$.
Is sin 50 the same as sin 130?
Yes. They are supplementary, so $\sin 130^\circ = \sin 50^\circ \approx 0.7660$; sine is positive in both the first and second quadrants.
Why can't I use sin 50 ≈ 50?
Because the small-angle rule uses radians and only works for small angles; at $50^\circ$ it gives $0.8727$, far from the true $0.7660$.
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Bhanzu Team
Content Creator and Editor
Bhanzu’s editorial team, known as Team Bhanzu, is made up of experienced educators, curriculum experts, content strategists, and fact-checkers dedicated to making math simple and engaging for learners worldwide. Every article and resource is carefully researched, thoughtfully structured, and rigorously reviewed to ensure accuracy, clarity, and real-world relevance. We understand that building strong math foundations can raise questions for students and parents alike. That’s why Team Bhanzu focuses on delivering practical insights, concept-driven explanations, and trustworthy guidance-empowering learners to develop confidence, speed, and a lifelong love for mathematics.
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