Sin 75 Degrees - Exact Value (√6+√2)/4 Explained

#Trigonometry
TL;DR
The value of sin 75 degrees is exactly 6+24\frac{\sqrt{6}+\sqrt{2}}{4}, about 0.9659. This article derives it by writing 75° as 45° + 30°, shows why sin⁡75°=cos⁡15°\sin 75° = \cos 15°, places the angle on the unit circle, and works through examples and common mistake.
BT
Bhanzu TeamLast updated on July 16, 20266 min read

The value of sin 75 degrees is 6+24≈0.9659\dfrac{\sqrt{6}+\sqrt{2}}{4} \approx 0.9659.

Quick Answer:

Result: sin⁡75°=6+24\sin 75° = \dfrac{\sqrt{6}+\sqrt{2}}{4}

Decimal: 0.96590.9659 (to four places)

In radians: sin⁡(5π12)=6+24\sin\left(\dfrac{5\pi}{12}\right) = \dfrac{\sqrt{6}+\sqrt{2}}{4}

Method shown: sum formula sin⁡(45°+30°)\sin(45°+30°)

Same as: cos⁡15°\cos 15° (complementary angle)

Quick Reference Table of Sine Values

Seventy-five degrees is built from 45°45° and 30°30°, and its sine sits high — the angle is close to 90°90°, where sine reaches 11. The table places it among the standard sine values in Quadrant I.

Angle (degrees)

Angle (radians)

sin⁡θ\sin\theta (exact)

sin⁡θ\sin\theta (decimal)

0°0°

00

00

0.00000.0000

15°15°

π12\dfrac{\pi}{12}

6−24\dfrac{\sqrt{6}-\sqrt{2}}{4}

0.25880.2588

30°30°

π6\dfrac{\pi}{6}

12\dfrac{1}{2}

0.50000.5000

45°45°

π4\dfrac{\pi}{4}

22\dfrac{\sqrt{2}}{2}

0.70710.7071

60°60°

π3\dfrac{\pi}{3}

32\dfrac{\sqrt{3}}{2}

0.86600.8660

75°75°

5π12\dfrac{5\pi}{12}

6+24\dfrac{\sqrt{6}+\sqrt{2}}{4}

0.96590.9659

90°90°

π2\dfrac{\pi}{2}

11

1.00001.0000

The top and bottom non-trivial entries are linked: sin⁡75°\sin 75° and sin⁡15°\sin 15° carry the same surds with opposite middle signs, because 75°75° and 15°15° are complementary. That is also why sin⁡75°\sin 75° matches cos⁡15°\cos 15° exactly.

What Sin 75 Degrees Means

On the unit circle — a circle of radius 11 centred at the origin — the sine of an angle is the yy-coordinate of the point where the angle's radius meets the circle. Rotating 75°75° counterclockwise from the positive xx-axis lands a point high in Quadrant I, at (cos⁡75°,sin⁡75°)\left(\cos 75°, \sin 75°\right), whose height above the xx-axis is sin⁡75°=6+24\sin 75° = \frac{\sqrt{6}+\sqrt{2}}{4}.

The right-triangle definition — opposite over hypotenuse — applies because 75°75° is acute, but 75°75° is not an angle you can read off a 3030-6060-9090 or 4545-4545-9090 triangle. So the value is built from the standard angles 45°45° and 30°30°.

How to Find the Value of Sin 75 Degrees

The direct route writes 75°75° as a sum of two standard angles. Two questions come up most.

Why does sin 75 equal cos 15? Because 75°75° and 15°15° add to 90°90°, so they are complementary, and the cofunction identity says sin⁡θ=cos⁡(90°−θ)\sin\theta = \cos(90° - \theta). So sin⁡75°=cos⁡(90°−75°)=cos⁡15°\sin 75° = \cos(90° - 75°) = \cos 15°, which is why both equal 6+24\frac{\sqrt{6}+\sqrt{2}}{4}. See cos 15 degrees for the same value reached from the other angle.

Method 1: The 45° + 30° sum formula

The sine sum identity is

sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B.\sin(A + B) = \sin A\cos B + \cos A\sin B.

Set A=45°A = 45°, B=30°B = 30°, and substitute sin⁡45°=22\sin 45° = \frac{\sqrt{2}}{2}, cos⁡30°=32\cos 30° = \frac{\sqrt{3}}{2}, cos⁡45°=22\cos 45° = \frac{\sqrt{2}}{2}, sin⁡30°=12\sin 30° = \frac{1}{2}:

sin⁡75°=sin⁡(45°+30°)=sin⁡45°cos⁡30°+cos⁡45°sin⁡30°\sin 75° = \sin(45° + 30°) = \sin 45°\cos 30° + \cos 45°\sin 30°

sin⁡75°=22⋅32+22⋅12\sin 75° = \frac{\sqrt{2}}{2}\cdot\frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2}\cdot\frac{1}{2}

sin⁡75°=64+24=6+24.\sin 75° = \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} = \frac{\sqrt{6}+\sqrt{2}}{4}.

Final answer: sin⁡75°=6+24≈0.9659.\sin 75° = \dfrac{\sqrt{6}+\sqrt{2}}{4} \approx 0.9659.

Method 2: The complement shortcut

Since sin⁡75°=cos⁡15°\sin 75° = \cos 15°, and cos⁡15°=6+24\cos 15° = \frac{\sqrt{6}+\sqrt{2}}{4} from the 45°−30°45° - 30° split, the value transfers directly:

sin⁡75°=cos⁡15°=6+24.\sin 75° = \cos 15° = \frac{\sqrt{6}+\sqrt{2}}{4}.

Examples of Sin 75 Degrees

Example 1

Evaluate 4sin⁡75°4\sin 75°.

4sin⁡75°=4⋅6+24=6+2≈3.863.4\sin 75° = 4\cdot\frac{\sqrt{6}+\sqrt{2}}{4} = \sqrt{6}+\sqrt{2} \approx 3.863.

Example 2

Find sin⁡75°\sin 75° by splitting the sine of a sum — the wrong way first.

A common first move is to add the sines: sin⁡75°=sin⁡45°+sin⁡30°=22+12≈1.207\sin 75° = \sin 45° + \sin 30° = \frac{\sqrt{2}}{2} + \frac{1}{2} \approx 1.207. That is impossible — sine never exceeds 11. Sine is not additive across angles. Use the sum identity:

sin⁡75°=sin⁡45°cos⁡30°+cos⁡45°sin⁡30°=6+24≈0.9659.\sin 75° = \sin 45°\cos 30° + \cos 45°\sin 30° = \frac{\sqrt{6}+\sqrt{2}}{4} \approx 0.9659.

A value above 11 is the instant signal that the sine was split incorrectly.

Example 3

Show that sin⁡75°+sin⁡15°=62\sin 75° + \sin 15° = \dfrac{\sqrt{6}}{2}, given sin⁡15°=6−24\sin 15° = \dfrac{\sqrt{6}-\sqrt{2}}{4}.

6+24+6−24=264=62.\frac{\sqrt{6}+\sqrt{2}}{4} + \frac{\sqrt{6}-\sqrt{2}}{4} = \frac{2\sqrt{6}}{4} = \frac{\sqrt{6}}{2}.

The 2\sqrt{2} terms cancel — the same cancellation seen on the sin 15 degrees page.

Example 4

Verify sin⁡275°+cos⁡275°=1\sin^2 75° + \cos^2 75° = 1, using cos⁡75°=6−24\cos 75° = \dfrac{\sqrt{6}-\sqrt{2}}{4}.

(6+24)2+(6−24)2=(8+212)+(8−212)16=1616=1.\left(\frac{\sqrt{6}+\sqrt{2}}{4}\right)^2 + \left(\frac{\sqrt{6}-\sqrt{2}}{4}\right)^2 = \frac{(8+2\sqrt{12}) + (8-2\sqrt{12})}{16} = \frac{16}{16} = 1.

The Pythagorean identity holds; the cross terms cancel.

Example 5

Express 75°75° in radians and state the value.

75°=75×π180=5π1275° = 75 \times \frac{\pi}{180} = \frac{5\pi}{12} radians, so sin⁡(5π12)=6+24\sin\left(\frac{5\pi}{12}\right) = \frac{\sqrt{6}+\sqrt{2}}{4}. Converting between radians and degrees leaves the value the same.

Common Mistakes With Sin 75 Degrees

Mistake 1: Adding the sines of the parts

Where it slips in: The first instinct on sin⁡(45°+30°)\sin(45° + 30°) is to add sin⁡45°\sin 45° and sin⁡30°\sin 30°.

Don't do this: sin⁡75°=sin⁡45°+sin⁡30°≈1.207\sin 75° = \sin 45° + \sin 30° \approx 1.207.

The correct way: Sine is not additive. Apply sin⁡(A+B)=sin⁡Acos⁡B+cos⁡Asin⁡B\sin(A+B) = \sin A\cos B + \cos A\sin B. The reliable habit is the range check — any sine result above 11 or below −1-1 is wrong before you finish.

Mistake 2: Assuming sin 75 equals cos 75

Where it slips in: Confusing the complement rule, which pairs sin⁡75°\sin 75° with cos⁡15°\cos 15°, not cos⁡75°\cos 75°.

Don't do this: Writing sin⁡75°=cos⁡75°\sin 75° = \cos 75°.

The correct way: The cofunction identity pairs an angle with its complement: sin⁡75°=cos⁡(90°−75°)=cos⁡15°\sin 75° = \cos(90° - 75°) = \cos 15°. The learner who half-remembers "sin equals cos" forgets the 90°−θ90° - \theta step — the fix is to always subtract the angle from 90°90°.

Mistake 3: Reporting only the decimal

Where it slips in: A calculator returns 0.96590.9659, but the question asks for the exact value.

Don't do this: Writing sin⁡75°=0.9659\sin 75° = 0.9659 when "exact" is required.

The correct way: Keep 6+24\frac{\sqrt{6}+\sqrt{2}}{4}. The decimal is rounded; the surd is exact.

Key Takeaways

  • Sin 75 degrees equals the exact surd 6+24\frac{\sqrt{6}+\sqrt{2}}{4}, about 0.96590.9659.

  • It is built by writing 75°75° as 45°+30°45° + 30° and applying the sine sum formula.

  • sin⁡75°=cos⁡15°\sin 75° = \cos 15° because 75°75° and 15°15° are complementary.

  • The most common error is adding the sines of the parts, which gives an impossible value above one.

Practice These Before Moving On

  1. Derive cos⁡75°\cos 75° from the 45°+30°45° + 30° split and confirm sin⁡275°+cos⁡275°=1\sin^2 75° + \cos^2 75° = 1.

  2. Use the complement rule to write sin⁡75°\sin 75° from cos⁡15°\cos 15° without re-deriving it.

  3. Convert 75°75° to radians and write the value as sin⁡(5π12)\sin\left(\frac{5\pi}{12}\right).

To go deeper into sum-and-difference values with a teacher, Bhanzu's trigonometry tutor and high school math tutor sessions cover the compound-angle and cofunction rules together, with math classes online for live practice.

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Frequently Asked Questions

What is the value of sin 75 degrees in fraction form?
6+24\frac{\sqrt{6}+\sqrt{2}}{4}, the same surd as cos⁡15°\cos 15°.
Is sin 75 degrees rational or irrational?
It contains 6\sqrt{6} and 2\sqrt{2}, so the decimal 0.9659258…0.9659258\ldots never terminates.
What is sin 75 degrees in radians?
sin⁡(5π12)=6+24\sin\left(\frac{5\pi}{12}\right) = \frac{\sqrt{6}+\sqrt{2}}{4}, since 75°=5π1275° = \frac{5\pi}{12}.
Why is sin 75 equal to cos 15?
Because 75°75° and 15°15° are complementary (they add to 90°90°), and sin⁡θ=cos⁡(90°−θ)\sin\theta = \cos(90° - \theta).
Is sin 75 the same as sin 105?
Yes. sin⁡105°=sin⁡(180°−105°)=sin⁡75°\sin 105° = \sin(180° - 105°) = \sin 75°, since supplementary angles share the same sine.
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