Sin 3pi/2 : Exact Value -1 and How to Find I

#Trigonometry
TL;DR
The value of sin 3pi/2 is exactly −1-1, the lowest point sine ever reaches, because the angle 3π2\dfrac{3\pi}{2} points straight down the negative yy-axis. This article shows the unit-circle reading, the degree twin 270∘270^\circ, a standard-angle table, worked examples, and where students slip.
BT
Bhanzu TeamLast updated on August 13, 20266 min read

What Does Sin 3pi/2 Mean?

Sine is one of the core trigonometric ratios in radians, and on the unit circle it is defined as the yy-coordinate of the point where the angle's radius meets the circle. A quadrantal angle is one whose terminal side falls on an axis rather than inside a quadrant.

So sin⁡3π2\sin\dfrac{3\pi}{2} asks: after rotating three-quarters of a full turn, how high above the horizontal axis does the point sit? It sits below the axis, at height −1-1, the deepest sine can go.

The negative sign is not a rounding artefact, it records that the point is below the xx-axis. Sine is negative for every angle whose terminal side dips beneath the horizontal.

Where Does Sin 3pi/2 Show Up?

Anything that swings between a high and a low (a spring, a tide, an alternating current written as sin⁡θ\sin\theta) hits its lowest value when the phase reaches 3π2\dfrac{3\pi}{2}. That is the trough of the wave, the mirror of the peak at π2\dfrac{\pi}{2}.

The value also anchors the four "corners" of the unit circle. Knowing that sin⁡3π2=−1\sin\dfrac{3\pi}{2} = -1 is what lets you sketch a sine graph from memory, because the trough is nailed down.

Standard-Angle Reference Table

3π2\dfrac{3\pi}{2} is a quadrantal angle, it lands exactly on an axis, not inside a quadrant. Here are the sine values at the four quadrantal angles, in radians and degrees.

Angle (radians)

Angle (degrees)

Terminal point

sin⁡θ\sin\theta

00

0∘0^\circ

(1,0)(1, 0)

00

π2\dfrac{\pi}{2}

90∘90^\circ

(0,1)(0, 1)

11

π\pi

180∘180^\circ

(−1,0)(-1, 0)

00

3π2\dfrac{3\pi}{2}

270∘270^\circ

(0,−1)(0, -1)

−1-1

Read the sine column and it swings 0→1→0→−10 \to 1 \to 0 \to -1 across the four quarter-turns. The minimum, −1-1, lands at 3π2\dfrac{3\pi}{2}.

How Do You Find The Value Of Sin 3pi/2?

Two routes lead to −1-1.

Method 1: Read the unit circle.

Rotate the radius counter-clockwise through three quarter-turns: past π2\dfrac{\pi}{2} (up), past π\pi (left), to 3π2\dfrac{3\pi}{2} (straight down). The tip lands at (0,−1)(0, -1).

sin⁡3π2=y-coordinate=−1\sin\frac{3\pi}{2} = y\text{-coordinate} = -1

Method 2: Convert to degrees.

Multiply by 180∘π\dfrac{180^\circ}{\pi}:

3π2×180∘π=270∘\frac{3\pi}{2} \times \frac{180^\circ}{\pi} = 270^\circ

At 270∘270^\circ the radius points straight down, so sin⁡270∘=−1\sin 270^\circ = -1. The degree form and the radian form name the same angle, so sin⁡3π2=sin⁡270∘=−1\sin\dfrac{3\pi}{2} = \sin 270^\circ = -1.

Because 270∘270^\circ sits on the negative yy-axis, no reference-angle triangle is needed here, the value is read directly off the axis.

Examples Of Sin 3pi/2

Example 1

Evaluate 4sin⁡3π24\sin\dfrac{3\pi}{2}.

4sin⁡3π2=4×(−1)=−44\sin\frac{3\pi}{2} = 4 \times (-1) = -4

Example 2

Find sin⁡3π2\sin\dfrac{3\pi}{2}. A student reasons that since 3π2\dfrac{3\pi}{2} is bigger than π\pi, the sine "must be positive like sin at the start".

Wrong attempt. Assuming sine stays positive because the angle is large.

That breaks at the axis test: 3π2\dfrac{3\pi}{2} points downward to (0,−1)(0, -1), and any point below the xx-axis has a negative yy-coordinate. So a positive answer contradicts the picture.

Correct. Sine is the yy-coordinate, and at (0,−1)(0, -1) that coordinate is −1-1. The size of the angle does not fix the sign; the position on the circle does.

Example 3

Evaluate sin⁡3π2+cos⁡3π2\sin\dfrac{3\pi}{2} + \cos\dfrac{3\pi}{2}.

sin⁡3π2=−1,cos⁡3π2=0\sin\frac{3\pi}{2} = -1, \qquad \cos\frac{3\pi}{2} = 0 sin⁡3π2+cos⁡3π2=−1+0=−1\sin\frac{3\pi}{2} + \cos\frac{3\pi}{2} = -1 + 0 = -1

Example 4

Verify sin⁡23π2+cos⁡23π2=1\sin^2\dfrac{3\pi}{2} + \cos^2\dfrac{3\pi}{2} = 1.

(−1)2+(0)2=1+0=1(-1)^2 + (0)^2 = 1 + 0 = 1

The Pythagorean identity checks out.

Example 5

A mass on a spring has vertical position y=sin⁡θy = \sin\theta. Find its position at θ=3π2\theta = \dfrac{3\pi}{2} and describe it.

y=sin⁡3π2=−1y = \sin\frac{3\pi}{2} = -1

The mass is at its lowest point, one unit below the rest line, the trough of its motion.

Where Students Trip Up On Sin 3pi/2

Mistake 1: Dropping the negative sign

Where it slips in: Recalling the size 11 but forgetting the angle points downward.

Don't do this: Writing sin⁡3π2=1\sin\dfrac{3\pi}{2} = 1. That is sin⁡π2\sin\dfrac{\pi}{2}, the peak, the opposite end of the wave.

The correct way: The point (0,−1)(0, -1) sits below the axis, so the yy-coordinate is −1-1. The memorizer who stores "sine of a quarter-ish angle is 11" without the sign is the one who loses the mark here.

Mistake 2: Reading the x-coordinate instead of the y

Where it slips in: At the axis points, students grab whichever coordinate is nonzero.

Don't do this: Writing sin⁡3π2=0\sin\dfrac{3\pi}{2} = 0 by copying the xx-coordinate.

The correct way: Sine is always the yy-coordinate. At (0,−1)(0, -1) that is −1-1; the 00 is the xx-coordinate and belongs to cosine.

Mistake 3: Converting 3π/2 to the wrong degree measure

Where it slips in: Rushing the radian-to-degree step and landing on 135∘135^\circ or 180∘180^\circ.

Don't do this: Writing 3π2=135∘\dfrac{3\pi}{2} = 135^\circ (that is 3π4\dfrac{3\pi}{4}).

The correct way: Multiply the whole angle by 180∘π\dfrac{180^\circ}{\pi}: 3π2×180∘π=270∘\dfrac{3\pi}{2}\times\dfrac{180^\circ}{\pi} = 270^\circ. Convert first, then read the circle.

Key Takeaways

  • Sin 3pi/2 equals −1-1, the minimum value the sine function reaches.

  • The angle 3π2\dfrac{3\pi}{2} is 270∘270^\circ; it points straight down to (0,−1)(0, -1), and sine reads that yy-coordinate.

  • The most common slip is dropping the negative sign and writing 11, that is sin⁡π2\sin\dfrac{\pi}{2}, the peak, not the trough.

  • As a quadrantal angle it needs no reference triangle, read it off the axis.

To build fluency with the whole unit circle alongside a teacher, explore Bhanzu's trigonometry tutor or a high school math tutor. The degree form of this angle is covered at sin 270°.

Practice These Before Moving On

  1. Evaluate 3sin⁡3π2+2cos⁡3π23\sin\dfrac{3\pi}{2} + 2\cos\dfrac{3\pi}{2}.

  2. Sketch one cycle of y=sin⁡θy = \sin\theta and mark the point at θ=3π2\theta = \dfrac{3\pi}{2}.

  3. An AC signal is v=sin⁡θv = \sin\theta. Find its value at θ=3π2\theta = \dfrac{3\pi}{2} and state whether it is a peak or a trough.

Want a live Bhanzu trainer to walk through more quadrantal-angle problems? Book a free demo class, online with an expert, anywhere.

For the formal picture of the four axis points, see the reference on the unit circle.

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Frequently Asked Questions

What is sin 3pi/2 in degrees?
3π2\dfrac{3\pi}{2} radians equals 270∘270^\circ, and sin⁡270∘=−1\sin 270^\circ = -1, the same value written with a different angle unit.
Why is sin 3pi/2 negative?
Because the terminal point (0,−1)(0, -1) sits below the horizontal axis, and sine reads the yy-coordinate, which is negative there.
Is sin 3pi/2 equal to sin pi/2?
No. sin⁡π2=1\sin\dfrac{\pi}{2} = 1 (the peak) and sin⁡3π2=−1\sin\dfrac{3\pi}{2} = -1 (the trough). They are mirror images across the axis.
What is cos 3pi/2?
cos⁡3π2=0\cos\dfrac{3\pi}{2} = 0, the xx-coordinate of the point (0,−1)(0, -1).
Does sin 3pi/2 need a reference angle?
No. It is a quadrantal angle sitting on an axis, so the value is read straight off the unit circle without a reference-angle triangle.
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