Cos 270 Degrees = 0 — Value, Unit Circle, Radians

#Trigonometry
TL;DR
The value of cos 270 degrees is exactly 00. In radians, 270°270° is 3π2\frac{3\pi}{2}, so cos⁡(270°)=cos⁡(3π2)=0\cos(270°) = \cos\left(\frac{3\pi}{2}\right) = 0. This article shows why three-quarters of a turn lands on the bottom of the unit circle where the xx-coordinate vanishes, gives a standard-angle reference table in degrees and radians, and clears up the common mix-ups.
BT
Bhanzu TeamLast updated on June 14, 20265 min read

Quick Answer:

  • Result: cos⁡270°=0\cos 270° = 0

  • Notation: cos⁡(3π2)=0\cos\left(\dfrac{3\pi}{2}\right) = 0 (radians)

  • Method shown: unit circle — the xx-coordinate at three-quarters of a turn

  • Approximate value: 00 (exact)

  • Exact form: 00

A rotation of 270°270° — three-quarters of the way around the unit circle, or 3π2\frac{3\pi}{2} radians — lands on the point at the very bottom, (0,−1)(0, -1). Cosine reads the xx-coordinate of where you land, and at the bottom of the circle that xx-coordinate is 00. The point sits directly below the center, so it has no horizontal offset at all.

Quick Reference Table — Cosine of Standard Angles

This table lists cosine at the standard angles in both degrees and radians, with 270°270° highlighted.

Angle (degrees)

Angle (radians)

cos⁡θ\cos\theta

0°0°

00

11

90°90°

π2\frac{\pi}{2}

00

180°180°

π\pi

−1-1

210°210°

7π6\frac{7\pi}{6}

−32-\frac{\sqrt{3}}{2}

225°225°

5π4\frac{5\pi}{4}

−22-\frac{\sqrt{2}}{2}

240°240°

4π3\frac{4\pi}{3}

−12-\frac{1}{2}

270°270°

3π2\frac{3\pi}{2}

00

300°300°

5π3\frac{5\pi}{3}

12\frac{1}{2}

315°315°

7π4\frac{7\pi}{4}

22\frac{\sqrt{2}}{2}

330°330°

11π6\frac{11\pi}{6}

32\frac{\sqrt{3}}{2}

360°360°

2π2\pi

11

Cosine crosses zero twice per turn — at 90°90° and again at 270°270°. Both are points where the circle is at its top or bottom, directly above or below the center, with no horizontal distance from the yy-axis.

Where cos 270 Degrees Appears

The value cos⁡270°=0\cos 270° = 0 marks a quarter-cycle turning point in any oscillation. In a cosine wave modelling a swinging pendulum or an AC voltage, the moment the phase reaches 270°270° is when the horizontal cosine component is exactly zero and the motion is passing through its midline.

The same zero defines the vertical axis in screen and robotics geometry: a heading of 270°270° points straight down, with no left-right component, which is why navigation and robotics control systems treat 270°270° as a pure-vertical bearing. Wherever a rotating quantity has "no horizontal part," cos⁡270°=0\cos 270° = 0 is the number saying so.

What is cos 270 Degrees?

Cosine of an angle is, on the unit circle, the xx-coordinate of the point reached by rotating that angle counterclockwise from the positive xx-axis. A turn of 270°270° covers three of the four quarter-turns.

That rotation lands on (0,−1)(0, -1) — the lowest point of the circle. The xx-coordinate there is 00, so cos⁡270°=0\cos 270° = 0. Written in radians the angle is 3π2\frac{3\pi}{2}, which is why cos⁡270°\cos 270° and cos⁡(3π2)\cos\left(\frac{3\pi}{2}\right) are the same number.

How To Find The Value of cos 270 Degrees

Method 1 — Unit circle

Rotate 270°270° counterclockwise from (1,0)(1, 0). Three quarter-turns put you at the bottom of the circle, the point (0,−1)(0, -1).

Cosine is the xx-coordinate of that point.

Final answer: cos⁡270°=0\cos 270° = 0.

Method 2 — Cosine subtraction formula

Write 270°270° as 360°−90°360° - 90° and apply cos⁡(A−B)=cos⁡Acos⁡B+sin⁡Asin⁡B\cos(A - B) = \cos A\cos B + \sin A\sin B:

cos⁡(360°−90°)=cos⁡360°cos⁡90°+sin⁡360°sin⁡90°\cos(360° - 90°) = \cos 360°\cos 90° + \sin 360°\sin 90°

=(1)(0)+(0)(1)=0= (1)(0) + (0)(1) = 0

Final answer: cos⁡270°=0\cos 270° = 0.

Method 3 — Co-function shift

Use cos⁡(270°)=cos⁡(180°+90°)=−cos⁡90°\cos(270°) = \cos(180° + 90°) = -\cos 90° via the periodic shift, and cos⁡90°=0\cos 90° = 0:

cos⁡270°=−cos⁡90°=−(0)=0\cos 270° = -\cos 90° = -(0) = 0

Zero has no sign, so the negative in front changes nothing here.

Common mistakes with cos 270 degrees

Mistake 1: Confusing cos 270° with sin 270°

Where it slips in: At 270°270° the unit-circle point is (0,−1)(0, -1), and the two coordinates get swapped.

Don't do this: Writing cos⁡270°=−1\cos 270° = -1 (that is sin⁡270°\sin 270°, the yy-coordinate).

The correct way: Cosine is the xx-coordinate, so cos⁡270°=0\cos 270° = 0; sine is the yy-coordinate, so sin⁡270°=−1\sin 270° = -1.

This swap is the recurring trap on quadrantal angles — a Mathway unit-circle walkthrough for cos⁡270°\cos 270° exists precisely because so many learners reach for −1-1.

Mistake 2: Calculator in degree vs radian mode

Where it slips in: Typing cos(270) while the calculator is set to radians.

Don't do this: Reading cos⁡(270 rad)≈0.984\cos(270 \text{ rad}) \approx 0.984 and reporting it as cos⁡270°\cos 270°.

The correct way: Use degree mode for cos⁡270°\cos 270°, or enter cos⁡(3π2)\cos\left(\frac{3\pi}{2}\right) in radian mode. Both give 00.

Mistake 3: Writing 0 with a sign

Where it slips in: Carrying the second-quadrant intuition that "cosine is negative here" into the answer.

Don't do this: Writing cos⁡270°=−0\cos 270° = -0 or treating the result as a small negative number.

The correct way: The result is exactly 00 — zero has no sign, so cos⁡270°=0\cos 270° = 0, plain.

Conclusion

  • Cos 270 degrees equals 00 — the cosine of three-quarters of a turn, written cos⁡(3π2)\cos\left(\frac{3\pi}{2}\right) in radians.

  • The rotation lands on (0,−1)(0, -1), the bottom of the unit circle, where the xx-coordinate is 00.

  • Three routes agree: unit circle, the subtraction formula on 360°−90°360° - 90°, and the co-function shift.

  • The most common slip is swapping cosine and sine — cos⁡270°=0\cos 270° = 0, sin⁡270°=−1\sin 270° = -1.

Quick self-check — try these

  1. Evaluate cos⁡270°+sin⁡270°\cos 270° + \sin 270°.

  2. Write cos⁡270°\cos 270° in radians and state its value.

  3. Explain in one sentence why cos⁡270°\cos 270° and cos⁡90°\cos 90° are equal.

If #1 didn't give −1-1, recheck the coordinates of the point at 270°270°. Want a live Bhanzu trainer to walk through more unit-circle problems? Book a free demo class — online globally.

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Frequently Asked Questions

What is the value of cos 270 degrees?
00. The same angle in radians is 3π2\frac{3\pi}{2}, so cos⁡(3π2)=0\cos\left(\frac{3\pi}{2}\right) = 0 too.
What is the exact value of cos 270 degrees?
Exactly 00 — no decimal approximation needed, since 270°270° sits on the yy-axis at (0,−1)(0, -1).
What is cos 270 degrees in radians?
270°270° equals 3π2\frac{3\pi}{2} radians, so cos⁡270°=cos⁡(3π2)=0\cos 270° = \cos\left(\frac{3\pi}{2}\right) = 0. The units differ; the value is the same.
Is cos 270° the same as cos 90°?
Yes, both equal 00. At 90°90° the point is (0,1)(0, 1) and at 270°270° it is (0,−1)(0, -1); the yy-coordinates differ, but both xx-coordinates are 00.
Is cos 270° positive or negative?
Neither — it is exactly 00. Zero is the boundary value cosine passes through between its positive and negative ranges.
✍️ Written By
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Bhanzu Team
Content Creator and Editor
Bhanzu’s editorial team, known as Team Bhanzu, is made up of experienced educators, curriculum experts, content strategists, and fact-checkers dedicated to making math simple and engaging for learners worldwide. Every article and resource is carefully researched, thoughtfully structured, and rigorously reviewed to ensure accuracy, clarity, and real-world relevance. We understand that building strong math foundations can raise questions for students and parents alike. That’s why Team Bhanzu focuses on delivering practical insights, concept-driven explanations, and trustworthy guidance-empowering learners to develop confidence, speed, and a lifelong love for mathematics.
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