Cos 7pi/4 : Exact Value, root 2 over 2, on the Unit Circle

#Trigonometry
TL;DR
The value of cos 7pi/4 is exactly 22\dfrac{\sqrt{2}}{2}, about 0.70710.7071, and it is positive. This article finds it with the reference angle π4\dfrac{\pi}{4} in the fourth quadrant, reads it off the unit circle, gives a standard-angle table, and works through examples and mistakes.
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Bhanzu TeamLast updated on August 11, 20265 min read

What Does Cos 7pi/4 Mean?

The four quadrants divide the plane by the axes: the fourth quadrant is the bottom-right, where the xx-coordinate is positive and the yy-coordinate is negative. The angle 7π4\dfrac{7\pi}{4} lands here, between 3π2\dfrac{3\pi}{2} and 2π2\pi.

The reference angle is the acute angle between the terminal side and the xx-axis. For 7π4\dfrac{7\pi}{4} it is 2π−7π4=π42\pi - \dfrac{7\pi}{4} = \dfrac{\pi}{4}. Cosine is the xx-coordinate on the unit circle, and since xx is positive in the fourth quadrant, cos⁡(7π4)\cos\left(\dfrac{7\pi}{4}\right) takes the positive π4\dfrac{\pi}{4} value.

Where Does Cos 7pi/4 Show Up?

A point rotating counterclockwise reaches 7π4\dfrac{7\pi}{4} just before completing a full turn, sitting low and to the right. Its cosine, the horizontal position, is still positive at 22\dfrac{\sqrt{2}}{2}, which is why a cosine wave has climbed most of the way back to its peak by this point.

The same value appears in any 45∘45^\circ diagonal viewed from the fourth quadrant on the unit circle, where the horizontal and vertical reaches are equal in size.

Standard-Angle Reference Table

The angle 7π4\dfrac{7\pi}{4} is 315∘315^\circ, one-eighth of a turn short of a full circle. Its cosine matches the 45∘45^\circ family, shown here for the first quadrant.

Angle (radians)

Angle (degrees)

cos⁡θ\cos\theta (exact)

cos⁡θ\cos\theta (decimal)

π6\dfrac{\pi}{6}

30∘30^\circ

32\dfrac{\sqrt{3}}{2}

0.86600.8660

π4\dfrac{\pi}{4}

45∘45^\circ

22\dfrac{\sqrt{2}}{2}

0.70710.7071

π3\dfrac{\pi}{3}

60∘60^\circ

12\dfrac{1}{2}

0.50000.5000

7π4\dfrac{7\pi}{4}

315∘315^\circ

22\dfrac{\sqrt{2}}{2}

0.70710.7071

The value equals that of its reference-angle sibling cos pi/4, because 7π4\dfrac{7\pi}{4} borrows the π4\dfrac{\pi}{4} cosine and keeps it positive.

How Do You Find The Exact Value Of Cos 7pi/4?

Method 1: Reference angle plus quadrant sign.

Find the reference angle, take its known cosine, then fix the sign from the quadrant.

Reference angle=2π−7π4=π4\text{Reference angle} = 2\pi - \frac{7\pi}{4} = \frac{\pi}{4}

The trigonometric ratios give cos⁡π4=22\cos\dfrac{\pi}{4} = \dfrac{\sqrt{2}}{2}. The fourth quadrant has a positive xx, so the sign stays positive:

cos⁡(7π4)=+22\cos\left(\frac{7\pi}{4}\right) = +\frac{\sqrt{2}}{2}

Method 2: The unit circle.

Sweep the radius by 7π4\dfrac{7\pi}{4} and it lands at (22,−22)\left(\dfrac{\sqrt{2}}{2}, -\dfrac{\sqrt{2}}{2}\right). Cosine is the xx-coordinate:

cos⁡(7π4)=22\cos\left(\frac{7\pi}{4}\right) = \frac{\sqrt{2}}{2}

The form 12\dfrac{1}{\sqrt{2}} is the same number; rationalising the denominator gives the standard 22\dfrac{\sqrt{2}}{2}.

Examples Of Cos 7pi/4

Example 1

Evaluate 4cos⁡(7π4)4\cos\left(\dfrac{7\pi}{4}\right).

4cos⁡(7π4)=4×22=22≈2.8284\cos\left(\frac{7\pi}{4}\right) = 4 \times \frac{\sqrt{2}}{2} = 2\sqrt{2} \approx 2.828

Example 2

A student places 7π4\dfrac{7\pi}{4} in the third quadrant and writes cos⁡(7π4)=−22\cos\left(\dfrac{7\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}. What went wrong?

Wrong attempt. Assuming any large angle is "past halfway and so negative," the student records −22-\dfrac{\sqrt{2}}{2}.

That misreads the quadrant: 7π4\dfrac{7\pi}{4} sits between 3π2\dfrac{3\pi}{2} and 2π2\pi, which is the fourth quadrant, not the third. In the fourth quadrant the xx-coordinate is positive, so cosine cannot be negative here.

Correct. The reference angle is π4\dfrac{\pi}{4} and the quadrant is fourth, so cos⁡(7π4)=+22\cos\left(\dfrac{7\pi}{4}\right) = +\dfrac{\sqrt{2}}{2}.

Example 3

Convert 7π4\dfrac{7\pi}{4} to degrees and confirm the value.

7π4×180∘π=315∘\frac{7\pi}{4} \times \frac{180^\circ}{\pi} = 315^\circ

Detail on this step lives at radians to degrees, and cos⁡315∘=22\cos 315^\circ = \dfrac{\sqrt{2}}{2}.

Example 4

Find sec⁡(7π4)\sec\left(\dfrac{7\pi}{4}\right) from the cosine.

Secant is the reciprocal of cosine:

sec⁡(7π4)=1cos⁡(7π4)=122=2\sec\left(\frac{7\pi}{4}\right) = \frac{1}{\cos\left(\frac{7\pi}{4}\right)} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2}

The matching page sec 7pi/4 works this through in full.

Example 5

Verify cos⁡2(7π4)+sin⁡2(7π4)=1\cos^2\left(\dfrac{7\pi}{4}\right) + \sin^2\left(\dfrac{7\pi}{4}\right) = 1, given sin⁡(7π4)=−22\sin\left(\dfrac{7\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}.

(22)2+(−22)2=12+12=1\left(\frac{\sqrt{2}}{2}\right)^2 + \left(-\frac{\sqrt{2}}{2}\right)^2 = \frac{1}{2} + \frac{1}{2} = 1

Where Students Trip Up On Cos 7pi/4

Mistake 1: Putting 7pi/4 in the wrong quadrant

Where it slips in: Guessing the quadrant from the size of the angle instead of the boundaries.

Don't do this: Calling 7π4\dfrac{7\pi}{4} a third-quadrant angle and making cosine negative.

The correct way: Compare against the quarter-turns: 7π4\dfrac{7\pi}{4} is past 3π2\dfrac{3\pi}{2} but short of 2π2\pi, so it is fourth-quadrant, where cosine is positive.

Mistake 2: Computing the reference angle from the wrong axis

Where it slips in: Subtracting from π\pi instead of 2π2\pi for a fourth-quadrant angle.

Don't do this: Writing the reference angle as 7π4−π=3π4\dfrac{7\pi}{4} - \pi = \dfrac{3\pi}{4}.

The correct way: In the fourth quadrant the reference angle is 2π−θ2\pi - \theta, so 2π−7π4=π42\pi - \dfrac{7\pi}{4} = \dfrac{\pi}{4}. The student who fixes the axis first stops producing reference angles larger than a right angle.

Mistake 3: Leaving cosine as 1 over root 2

Where it slips in: Stopping at the unrationalised form on a graded answer.

Don't do this: Writing cos⁡(7π4)=12\cos\left(\dfrac{7\pi}{4}\right) = \dfrac{1}{\sqrt{2}} and treating it as final.

The correct way: Rationalise the denominator to the standard 22\dfrac{\sqrt{2}}{2}; the two forms are equal, but 22\dfrac{\sqrt{2}}{2} is the expected exact answer.

Key Takeaways

  • Cos 7pi/4 equals 22\dfrac{\sqrt{2}}{2}, about 0.70710.7071, and it is positive.

  • 7π4\dfrac{7\pi}{4} is 315∘315^\circ, a fourth-quadrant angle with reference angle π4\dfrac{\pi}{4}.

  • Reference angle sets the size, quadrant sets the sign: fourth-quadrant cosine stays positive.

  • Rationalise 12\dfrac{1}{\sqrt{2}} to the standard 22\dfrac{\sqrt{2}}{2} for the final answer.

To master reference angles alongside a teacher, explore Bhanzu's trigonometry tutor, its high school math tutor programme, or live math classes online.

Practice These Before Moving On

  1. Evaluate 2cos⁡(7π4)−22\cos\left(\dfrac{7\pi}{4}\right) - \sqrt{2}.

  2. State the reference angle and quadrant of 7π4\dfrac{7\pi}{4}, then give its cosine.

  3. Find cos⁡(5π4)\cos\left(\dfrac{5\pi}{4}\right) and explain why its sign differs from cos⁡(7π4)\cos\left(\dfrac{7\pi}{4}\right).

Want a live Bhanzu trainer to walk through more cos 7pi/4 problems? Book a free demo class.

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Frequently Asked Questions

What is the exact value of cos 7pi/4?
22\dfrac{\sqrt{2}}{2}, about 0.70710.7071, and it is positive.
Is cos 7pi/4 positive or negative?
Positive. 7π4\dfrac{7\pi}{4} is in the fourth quadrant, where the xx-coordinate, and so cosine, is positive.
What is cos 7pi/4 in degrees?
7π4\dfrac{7\pi}{4} is 315∘315^\circ, and cos⁡315∘=22\cos 315^\circ = \dfrac{\sqrt{2}}{2}.
What is the reference angle for 7pi/4?
π4\dfrac{\pi}{4}, found as 2π−7π42\pi - \dfrac{7\pi}{4}.
Why does cos 7pi/4 equal cos pi/4?
Both share the reference angle π4\dfrac{\pi}{4}, and both sit where cosine is positive, so their cosines are the same 22\dfrac{\sqrt{2}}{2}.
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