Cos 45 Degrees - Exact Value √2/2 and How to Find It

What Does Cos 45 Degrees Mean?

Cosine is one of the three core trigonometric ratios - in a right triangle, the cosine of an angle is the side adjacent to it divided by the hypotenuse. So $\cos 45^\circ$ asks: in a right triangle with a $45^\circ$ angle, what fraction of the hypotenuse is the adjacent side?

On the unit circle, the cosine of an angle is the $x$-coordinate of the point where the angle's radius meets the circle. At $45^\circ$ that point is $\left(\dfrac{\sqrt{2}}{2}, \dfrac{\sqrt{2}}{2}\right)$, so the $x$-coordinate, and therefore the cosine, is $\dfrac{\sqrt{2}}{2}$. In radian measure the same angle is $\dfrac{\pi}{4}$.

Where Does Cos 45 Degrees Show Up?

A $45^\circ$ angle is the exact diagonal - equal reach horizontally and vertically - so it appears wherever something splits its motion evenly between two directions. A projectile launched at $45^\circ$ gets the maximum range because its horizontal and vertical components, both scaled by $\dfrac{\sqrt{2}}{2}$, are balanced.

The same value sets the diagonal of a unit square, whose corner-to-corner line makes $45^\circ$ with each side. On the unit circle, $\cos 45^\circ = \dfrac{\sqrt{2}}{2}$ is the horizontal coordinate of that perfectly diagonal direction, which is why the cosine function returns it for every $45^\circ$ turn.

Standard-Angle Reference Table

Forty-five degrees is one of the handful of angles whose cosine has a clean exact form. Here are the standard first-quadrant angles in both degrees and radians.

Read the cosine column top to bottom and it slides from $1$ down to $0$. Forty-five degrees is the one angle where sine and cosine meet: $\cos 45^\circ = \sin 45^\circ = \dfrac{\sqrt{2}}{2}$, because the point sits on the line $y = x$.

How Do You Find The Exact Value Of Cos 45 Degrees?

There are two clean routes: one builds the value from a triangle, the other reads it off the unit circle. Both give $\dfrac{\sqrt{2}}{2}$.

Method 1: The 45-45-90 triangle.

Take a right triangle with a $45^\circ$ angle. The other non-right angle is also $45^\circ$, so the two legs are equal. Let each leg be $1$.

By the Pythagorean theorem the hypotenuse is $\sqrt{1^2 + 1^2} = \sqrt{2}$. Now apply the definition:

$$\cos 45^\circ = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}$$

The last step rationalises the denominator by multiplying top and bottom by $\sqrt{2}$, giving the standard form $\dfrac{\sqrt{2}}{2}$.

Method 2: The unit circle.

Set the radius to $1$ and rotate it $45^\circ$ above the positive $x$-axis. The tip lands at $\left(\dfrac{\sqrt{2}}{2}, \dfrac{\sqrt{2}}{2}\right)$.

$$\cos 45^\circ = x\text{-coordinate} = \frac{\sqrt{2}}{2}$$

The two methods agree because the unit circle is the 45-45-90 triangle scaled so the hypotenuse equals $1$. In radians this is written $\cos \dfrac{\pi}{4}$, the same value from a radian entry point at cos pi/4.

Examples Of Cos 45 Degrees

Example 1

Evaluate $6\cos 45^\circ$.

$$6\cos 45^\circ = 6 \times \frac{\sqrt{2}}{2} = 3\sqrt{2} \approx 4.243$$

Example 2

Find $\cos 45^\circ$ in fraction form, starting from the 45-45-90 triangle.

Wrong attempt. A student sets the legs to $1$ and the hypotenuse to $2$ by "adding the legs," then writes $\cos 45^\circ = \dfrac{1}{2}$.

That breaks the triangle: the hypotenuse is not the sum of the legs. By the Pythagorean theorem it is $\sqrt{1^2 + 1^2} = \sqrt{2} \approx 1.414$, not $2$, so $\dfrac{1}{2}$ is too small.

Correct. With hypotenuse $\sqrt{2}$, $\cos 45^\circ = \dfrac{1}{\sqrt{2}} = \dfrac{\sqrt{2}}{2} \approx 0.7071$.

Example 3

A right triangle has a hypotenuse of $8$ cm and a $45^\circ$ angle. Find the side adjacent to that angle.

$$\cos 45^\circ = \frac{\text{adjacent}}{8} \implies \text{adjacent} = 8 \times \frac{\sqrt{2}}{2} = 4\sqrt{2} \approx 5.657 \text{ cm}$$

Example 4

Verify the identity $\cos^2 45^\circ + \sin^2 45^\circ = 1$.

$$\left(\frac{\sqrt{2}}{2}\right)^2 + \left(\frac{\sqrt{2}}{2}\right)^2 = \frac{1}{2} + \frac{1}{2} = 1$$

The Pythagorean identity holds, as it must for every angle.

Example 5

Express $\cos 45^\circ$ in radians and evaluate $\cos \dfrac{\pi}{4}$.

Since $45^\circ = \dfrac{\pi}{4}$ radians, $\cos \dfrac{\pi}{4} = \cos 45^\circ = \dfrac{\sqrt{2}}{2}$. The radian form and the degree form name the same angle and the same value, which is why the sin cos tan table lists one entry for both.

Where Students Trip Up On Cos 45 Degrees

Mistake 1: Writing the hypotenuse as 2 instead of √2

Where it slips in: Building the 45-45-90 triangle, when a reader adds the legs instead of using the Pythagorean theorem.

Don't do this: Setting legs $1$ and $1$ and calling the hypotenuse $2$, which gives $\cos 45^\circ = \dfrac{1}{2}$.

The correct way: The hypotenuse is $\sqrt{1^2 + 1^2} = \sqrt{2}$, so $\cos 45^\circ = \dfrac{1}{\sqrt{2}} = \dfrac{\sqrt{2}}{2}$. Students who reach for the shortest arithmetic reliably add the legs here.

Mistake 2: Leaving the answer unrationalised or as a rounded decimal

Where it slips in: Calculator-first solving, where the screen reads $0.707$ and the student copies that.

Don't do this: Writing $\cos 45^\circ = 0.707$ on a problem that asks for the exact value, or stopping at $\dfrac{1}{\sqrt{2}}$ with a root in the denominator.

The correct way: Give the standard rationalised form $\dfrac{\sqrt{2}}{2}$. The decimal $0.7071$ is an approximation; $\dfrac{\sqrt{2}}{2}$ is the value.

Mistake 3: Confusing cos 45° with cos 135°

Where it slips in: Second-quadrant problems, when the sign is dropped.

Don't do this: Writing $\cos 135^\circ = \dfrac{\sqrt{2}}{2}$ by copying the $45^\circ$ value without the quadrant sign.

The correct way: They share the size but not the sign — $\cos 45^\circ = \dfrac{\sqrt{2}}{2}$, while cos 135 degrees $= -\dfrac{\sqrt{2}}{2}$ because $135^\circ$ sits in Quadrant II.

Key Takeaways

• Cos 45 degrees equals $\dfrac{\sqrt{2}}{2}$, approximately $0.7071$ — an exact value because $45^\circ$ is a standard angle.

• The 45-45-90 triangle gives it as $\dfrac{1}{\sqrt{2}} = \dfrac{\sqrt{2}}{2}$; the unit circle gives it as the $x$-coordinate at $45^\circ$.

• It equals $\sin 45^\circ$ and, in radians, $\cos \dfrac{\pi}{4}$; only the sign changes at $135^\circ$.

• To take $\cos 45^\circ$ further with a teacher, explore Bhanzu's trigonometry tutor, a high school math tutor, or live math classes online.

Practice These Before Moving On

1. Evaluate $2\cos 45^\circ + \tan 45^\circ$.

2. A ramp rises at $45^\circ$ over a horizontal run of $3$ m. Use $\cos 45^\circ$ to find the ramp's slope length.

3. Show that $\cos 45^\circ \times \cos 45^\circ + \sin 45^\circ \times \sin 45^\circ = 1$.

Want a live Bhanzu trainer to walk through more cos 45 degrees problems? Book a free demo class.

Read More

• Cos 0 Degrees — the starting value of the standard-angle table.

• Cos 40 Degrees — the nearby non-special angle handled as a decimal.

• Trigonometric Ratios Of Specific Angles — every standard-angle sine, cosine, and tangent derived.

• Trigonometric Table — sine, cosine, and tangent for every standard angle in one chart.