Cos 50 Degrees : Value 0.6428 and How to Find It

#Trigonometry
TL;DR
The value of cos 50 degrees is approximately 0.64280.6428. Because 50∘50^\circ is not one of the standard angles, it has no clean radical form, so this article shows how to find it by calculator, why cos⁡50∘=sin⁡40∘\cos 50^\circ = \sin 40^\circ, where it sits between the special angles, and the mistakes students make.
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Bhanzu TeamLast updated on August 11, 20267 min read

What Does Cos 50 Degrees Mean?

Cosine is one of the three core trigonometric ratios: in a right triangle, the cosine of an angle is the side adjacent to it divided by the hypotenuse. So cos⁡50∘\cos 50^\circ asks what fraction of the hypotenuse the adjacent side is when the angle is 50∘50^\circ.

On the unit circle, the cosine of an angle is the xx-coordinate of the point where the angle's radius meets the circle. At 50∘50^\circ that point is about (0.6428,0.766)(0.6428, 0.766), and since 50∘50^\circ lies in the first quadrant, the cosine is positive. The cosine function returns this same 0.64280.6428 every time the angle comes back to 50∘50^\circ.

Where Does Cos 50 Degrees Show Up?

A 50∘50^\circ angle is common in the physical world even though its cosine is not a special value. A roof pitched at 50∘50^\circ, a support strut leaning at 50∘50^\circ, or a projectile launched at 50∘50^\circ all need cos⁡50∘\cos 50^\circ to resolve the horizontal component of a length or velocity. Because the answer is a measured decimal, engineers and surveyors read it off a calculator to the precision the job needs, not off a table of exact forms.

Standard-Angle Reference Table

Fifty degrees sits between two special angles, and comparing them shows why its cosine is a plain decimal rather than a tidy radical.

Angle (degrees)

cos⁡θ\cos\theta (exact)

cos⁡θ\cos\theta (decimal)

30∘30^\circ

32\dfrac{\sqrt{3}}{2}

0.86600.8660

45∘45^\circ

22\dfrac{\sqrt{2}}{2}

0.70710.7071

50∘50^\circ

no simple radical

0.64280.6428

60∘60^\circ

12\dfrac{1}{2}

0.50000.5000

Cosine shrinks as the angle grows, so cos⁡50∘\cos 50^\circ lands between cos 45 degrees and cos 60 degrees - closer to the middle of that gap. Unlike its neighbours, 50∘50^\circ carries no clean surd, which is exactly what makes it a calculator value rather than one to memorise.

How Do You Find The Exact Value Of Cos 50 Degrees?

Here is the honest answer: 50∘50^\circ is not a special angle, so there is no short exact form to write down. A closed form exists, but it is a messy nested radical from solving a cubic, and no exam expects it. Finding cos⁡50∘\cos 50^\circ is a calculator and approximation skill, not a memorisation target. Three routes get you a trustworthy number.

Method 1: The calculator.

Set the calculator to degree mode and enter cos⁡(50)\cos(50):

cos⁡50∘=0.642787…≈0.6428\cos 50^\circ = 0.642787\ldots \approx 0.6428

Method 2: The cofunction relationship.

Cosine and sine are cofunctions, linked by the cofunction identities: cos⁡θ=sin⁡(90∘−θ)\cos\theta = \sin(90^\circ - \theta). So

cos⁡50∘=sin⁡(90∘−50∘)=sin⁡40∘≈0.6428\cos 50^\circ = \sin(90^\circ - 50^\circ) = \sin 40^\circ \approx 0.6428

This does not make 50∘50^\circ special, but it lets you swap in a sine value if that is what your problem gives you.

Method 3: Bounding between special angles.

You can sanity-estimate without a calculator. Since cos⁡45∘≈0.7071\cos 45^\circ \approx 0.7071 and cos⁡60∘=0.5\cos 60^\circ = 0.5, and 50∘50^\circ sits between them, cos⁡50∘\cos 50^\circ must fall between 0.50.5 and 0.70710.7071. The decimal 0.64280.6428 passes that check. For the precise definition of cosine as a function, see Wolfram MathWorld's cosine entry.

Examples Of Cos 50 Degrees

Example 1

Evaluate 10cos⁡50∘10\cos 50^\circ.

10cos⁡50∘=10×0.6428=6.42810\cos 50^\circ = 10 \times 0.6428 = 6.428

Example 2

Find cos⁡50∘\cos 50^\circ without a calculator by splitting the angle.

Wrong attempt. A student writes cos⁡50∘=cos⁡45∘+cos⁡5∘≈0.7071+0.9962=1.7033\cos 50^\circ = \cos 45^\circ + \cos 5^\circ \approx 0.7071 + 0.9962 = 1.7033.

That is impossible: cosine never exceeds 11, so an answer above 1.71.7 is wrong on sight. Cosine is not additive, so cos⁡(45∘+5∘)\cos(45^\circ + 5^\circ) is not cos⁡45∘+cos⁡5∘\cos 45^\circ + \cos 5^\circ.

Correct. The angle-sum identity is cos⁡(A+B)=cos⁡Acos⁡B−sin⁡Asin⁡B\cos(A + B) = \cos A\cos B - \sin A\sin B:

cos⁡50∘=cos⁡45∘cos⁡5∘−sin⁡45∘sin⁡5∘≈0.7044−0.0617=0.6427\cos 50^\circ = \cos 45^\circ\cos 5^\circ - \sin 45^\circ\sin 5^\circ \approx 0.7044 - 0.0617 = 0.6427

which matches the calculator value.

Example 3

Verify that cos⁡50∘=sin⁡40∘\cos 50^\circ = \sin 40^\circ.

sin⁡40∘≈0.6428=cos⁡50∘\sin 40^\circ \approx 0.6428 = \cos 50^\circ

The cofunction relationship holds because 50∘50^\circ and 40∘40^\circ are complementary.

Example 4

A brace leans against a wall with its foot 88 m from the base, meeting the ground at 50∘50^\circ. How long is the brace?

The horizontal run is the adjacent side, so:

cos⁡50∘=8brace  ⟹  brace=80.6428≈12.45 m\cos 50^\circ = \frac{8}{\text{brace}} \implies \text{brace} = \frac{8}{0.6428} \approx 12.45 \text{ m}

Example 5

Check that cos⁡250∘+sin⁡250∘=1\cos^2 50^\circ + \sin^2 50^\circ = 1.

(0.6428)2+(0.766)2=0.4132+0.5868=1.0000(0.6428)^2 + (0.766)^2 = 0.4132 + 0.5868 = 1.0000

The Pythagorean identity holds for 50∘50^\circ as it does for every angle.

Where Students Trip Up On Cos 50 Degrees

Mistake 1: Inventing a radical for a non-special angle

Where it slips in: Seeing 50∘50^\circ near 45∘45^\circ and 60∘60^\circ and assuming it must have a clean surd too.

Don't do this: Writing something like cos⁡50∘=2.62\cos 50^\circ = \dfrac{\sqrt{2.6}}{2}. The first instinct for many students is to force every angle into a radical, but only a short list of angles has one.

The correct way: Report cos⁡50∘≈0.6428\cos 50^\circ \approx 0.6428 and say plainly that 50∘50^\circ has no simple exact form. Rounding to a decimal is the right answer here, not a shortcoming.

Mistake 2: Adding cosines of split angles

Where it slips in: Breaking 50∘50^\circ into 45∘+5∘45^\circ + 5^\circ and adding the cosines.

Don't do this: Writing cos⁡(45∘+5∘)=cos⁡45∘+cos⁡5∘\cos(45^\circ + 5^\circ) = \cos 45^\circ + \cos 5^\circ, which gives a value above 11.

The correct way: Use cos⁡(A+B)=cos⁡Acos⁡B−sin⁡Asin⁡B\cos(A + B) = \cos A\cos B - \sin A\sin B. Cosine mixes the two angles, it does not add across them.

Mistake 3: Reading the answer in radian mode

Where it slips in: A calculator left in radian mode returns cos⁡(50)≈0.965\cos(50) \approx 0.965 instead of 0.64280.6428.

Don't do this: Trusting the screen without confirming the angle unit.

The correct way: Confirm degree mode before entering cos⁡(50)\cos(50). Radian-versus-degree confusion is a well-known source of error in engineering and graphics software, where an angle fed in the wrong unit silently produces a wrong length - the fix is always to check the unit first.

Key Takeaways

  • Cos 50 degrees is approximately 0.64280.6428 - a decimal value, because 50∘50^\circ is not a special angle and has no simple radical.

  • It sits between cos⁡45∘≈0.7071\cos 45^\circ \approx 0.7071 and cos⁡60∘=0.5\cos 60^\circ = 0.5, a quick way to sanity-check the number.

  • cos⁡50∘=sin⁡40∘\cos 50^\circ = \sin 40^\circ through the cofunction relationship of complementary angles.

  • The common slips are inventing a radical, adding cosines of split angles, and leaving the calculator in radian mode.

To build angle sense with a teacher, explore Bhanzu's trigonometry tutor sessions, a high school math tutor, or a math tutor for one-to-one practice.

Practice These Before Moving On

  1. Estimate cos⁡55∘\cos 55^\circ by bounding it between cos⁡45∘\cos 45^\circ and cos⁡60∘\cos 60^\circ, then check with a calculator.

  2. A rope meets the ground at 50∘50^\circ and is 1515 m long. Find its horizontal reach using cos⁡50∘\cos 50^\circ.

  3. Use the cofunction relationship to rewrite cos⁡50∘\cos 50^\circ as a sine, then confirm the two decimals match.

Want a live Bhanzu trainer to work through non-special angles and calculator technique? Book a free demo class.

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Frequently Asked Questions

Is cos 50 degrees a rational number?
No. It is an irrational decimal, 0.642787…0.642787\ldots, that never terminates or repeats.
What is cos 50 degrees in radians?
50∘50^\circ equals 5π18\dfrac{5\pi}{18} radians, and cos⁡(5π18)≈0.6428\cos\left(\dfrac{5\pi}{18}\right) \approx 0.6428 - the same value in a different angle unit.
Why does cos 50 degrees have no exact value?
It does have an exact closed form, but it is a complicated nested radical from a cubic equation, so in practice 50∘50^\circ is treated as a calculator value, not a special angle.
Is cos 50 the same as sin 40?
Yes. Since 50∘50^\circ and 40∘40^\circ add to 90∘90^\circ, they are complementary, so cos⁡50∘=sin⁡40∘\cos 50^\circ = \sin 40^\circ.
✍️ Written By
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Bhanzu Team
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Bhanzu’s editorial team, known as Team Bhanzu, is made up of experienced educators, curriculum experts, content strategists, and fact-checkers dedicated to making math simple and engaging for learners worldwide. Every article and resource is carefully researched, thoughtfully structured, and rigorously reviewed to ensure accuracy, clarity, and real-world relevance. We understand that building strong math foundations can raise questions for students and parents alike. That’s why Team Bhanzu focuses on delivering practical insights, concept-driven explanations, and trustworthy guidance-empowering learners to develop confidence, speed, and a lifelong love for mathematics.
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