What Is Subtracting Fractions With Unlike Denominators?
Subtracting fractions with unlike denominators means finding the difference between two fractions whose bottom numbers are different, such as $\frac{3}{4} - \frac{2}{5}$. Because the two fractions describe pieces of different sizes, you cannot subtract them directly. You first rewrite both fractions so they share a single common denominator, and only then subtract.
The denominator is the bottom number of a fraction, and it tells you how many equal parts the whole is split into. The numerator, the top number, tells you how many of those parts you have. When two fractions have the same denominator they are called like fractions; when the denominators differ, as in $\frac{3}{4}$ and $\frac{2}{5}$, they are unlike fractions.
The whole procedure rests on one idea: pieces can only be added or removed once they are the same size. A quarter and a fifth are different-sized pieces, so the first job is always to rewrite them as pieces of a matching size.
How Do You Subtract Fractions With Unlike Denominators?
Follow four steps in order. We will use $\frac{3}{4} - \frac{2}{5}$ as the running example.
Step 1: Find the least common denominator (LCD). The LCD is the least common multiple of the two denominators. Multiples of $4$ are $4, 8, 12, 16, 20, \dots$ and multiples of $5$ are $5, 10, 15, 20, \dots$. The smallest number in both lists is $20$, so the LCD is $20$.
Step 2: Rewrite each fraction as an equivalent fraction over the LCD. Multiply the top and bottom of each fraction by whatever turns its denominator into $20$.
$$\frac{3}{4} = \frac{3 \times 5}{4 \times 5} = \frac{15}{20}, \qquad \frac{2}{5} = \frac{2 \times 4}{5 \times 4} = \frac{8}{20}$$
Step 3: Subtract the numerators, keep the denominator. With matching denominators the pieces are now the same size, so remove one numerator from the other.
$$\frac{15}{20} - \frac{8}{20} = \frac{15 - 8}{20} = \frac{7}{20}$$
Step 4: Simplify. Reduce the answer if the numerator and denominator share a common factor. Here $7$ and $20$ share no factor greater than $1$, so $\frac{7}{20}$ is already in lowest terms.
$$\frac{3}{4} - \frac{2}{5} = \frac{7}{20}$$
What Is The Cross-Multiplication Shortcut?
When you are subtracting exactly two fractions, there is a fast route that skips the search for the LCD. For any two fractions, the difference can be written in one line:
$$\frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}$$
The new denominator is the product of the two original denominators, and the new numerator cross-multiplies each numerator with the other denominator. Applied to the same example:
$$\frac{3}{4} - \frac{2}{5} = \frac{(3)(5) - (2)(4)}{(4)(5)} = \frac{15 - 8}{20} = \frac{7}{20}$$
The result matches the four-step method exactly. One caution: the shortcut uses $bd$, which is a common denominator but not always the least one. If the two denominators share a factor, such as $6$ and $4$, the product $24$ is larger than the LCD $12$, so you may have more simplifying to do at the end. The shortcut is quickest for two small fractions; the LCD method scales better to three or more.
How Do You Subtract When One Answer Needs Simplifying?
Most exam fractions do not land in lowest terms on their own, so Step 4 matters. Take $\frac{5}{6} - \frac{1}{3}$.
The LCD of $6$ and $3$ is $6$, since $6$ is already a multiple of $3$. Only the second fraction needs rewriting:
$$\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}$$
Now subtract the numerators over the shared denominator:
$$\frac{5}{6} - \frac{2}{6} = \frac{3}{6}$$
The numerator and denominator of $\frac{3}{6}$ share a common factor of $3$, so divide both by $3$:
$$\frac{3}{6} = \frac{3 \div 3}{6 \div 3} = \frac{1}{2}$$
Final answer: $\frac{5}{6} - \frac{1}{3} = \frac{1}{2}$. An answer left as $\frac{3}{6}$ is not wrong in value, but it is not fully reduced, and reduced form is what most marking schemes expect.
How Do You Subtract Mixed Numbers With Unlike Denominators?
A mixed number has a whole part and a fraction part, such as $3\frac{1}{4}$. To subtract mixed numbers with unlike denominators, give the fraction parts a common denominator first, then subtract the whole parts and the fraction parts. Sometimes the fraction part on top is smaller than the one below it, and then you borrow one whole.
Take $3\frac{1}{4} - 1\frac{5}{6}$.
The LCD of $4$ and $6$ is $12$, so rewrite both fraction parts:
$$3\frac{1}{4} = 3\frac{3}{12}, \qquad 1\frac{5}{6} = 1\frac{10}{12}$$
The top fraction $\frac{3}{12}$ is smaller than $\frac{10}{12}$, so borrow one whole from the $3$. One whole is $\frac{12}{12}$, which turns $3\frac{3}{12}$ into $2\frac{15}{12}$:
$$2\frac{15}{12} - 1\frac{10}{12} = (2 - 1) + \frac{15 - 10}{12} = 1\frac{5}{12}$$
Final answer: $3\frac{1}{4} - 1\frac{5}{6} = 1\frac{5}{12}$. If borrowing feels error-prone, convert each mixed number to an improper fraction first ($\frac{13}{4} - \frac{11}{6}$), subtract as usual, then convert back. Both routes give $1\frac{5}{12}$.
Why Must The Denominators Be The Same Before You Subtract?
The rule "find a common denominator first" is not an arbitrary hoop. It comes straight from what a fraction means.
Fractions are counts of equal pieces. The fraction $\frac{3}{4}$ means "three pieces, each one-quarter of a whole." The fraction $\frac{2}{5}$ means "two pieces, each one-fifth." You cannot take two fifth-sized pieces away from three quarter-sized pieces directly, because the pieces are not the same size. Subtraction only counts objects that match.
A common denominator re-cuts both wholes the same way. Rewriting as $\frac{15}{20}$ and $\frac{8}{20}$ re-slices both wholes into twentieths. Now every piece is identical in size, so $15$ pieces minus $8$ pieces genuinely leaves $7$ pieces, and the answer $\frac{7}{20}$ is trustworthy.
The denominator is a label, not a quantity to combine. The bottom number names the piece size. Subtracting the denominators would be like subtracting the units off a measurement, it changes what you are counting rather than how much. That is the deep reason the denominator stays fixed while only the numerators change.
Who Invented Fraction Notation?
Fractions are older than almost any other piece of written mathematics, and the neat bar we use today took thousands of years to arrive.
Two later figures gave us the notation on the page today:
Abu Bakr al-Hassar (12th century, Morocco) is credited with the horizontal fraction bar, writing the numerator above and the denominator below a line, the exact layout still in use.
Leonardo of Pisa, known as Fibonacci (c. 1170 to c. 1250, Italy), spread the bar notation across Europe through his book Liber Abaci in 1202, alongside the Hindu-Arabic digits.
Where Is Subtracting Fractions Used In The Real World?
Taking one fraction from another with different denominators shows up far beyond the worksheet.
Cooking and baking: halving a recipe that calls for $\frac{3}{4}$ cup while you already have $\frac{1}{3}$ cup measured means subtracting unlike fractions to find how much more to add.
Construction and woodworking: a board $\frac{7}{8}$ inch thick planed down by $\frac{1}{16}$ inch, or a gap measured in different fraction scales, is an unlike-denominator subtraction.
Money and time: working out how much of an hour is left after $\frac{1}{3}$ is spent on one task and $\frac{1}{4}$ on another relies on the same LCD step.
Music: note lengths are fractions of a beat, and a musician subtracts a $\frac{1}{8}$ note from a $\frac{1}{2}$ rest using a common denominator to keep the bar in time.
The same four steps serve a baker, a carpenter, and a composer, which is a small reminder that one clean procedure quietly runs many trades.
What Are The Most Common Subtracting Fractions With Unlike Denominators Mistakes?
These four errors account for most lost marks on this topic, verified against the common-mistakes notes on Albert.io and the error summaries surfaced by Cuemath, HowStuffWorks, and SplashLearn.
Subtracting the denominators too.
Where it slips in:
A student computes $\frac{3}{4} - \frac{2}{5}$ as $\frac{3-2}{4-5}$, treating top and bottom the same way.
Don't do this:
Do not subtract the bottom numbers. The denominator names the piece size, it is not a quantity to combine.
The correct way:
Rewrite over a common denominator, then subtract only the numerators and keep the shared denominator: $\frac{15}{20} - \frac{8}{20} = \frac{7}{20}$.
Subtracting numerators before finding a common denominator.
Where it slips in:
A student writes $\frac{5}{6} - \frac{1}{3} = \frac{5-1}{6}=\frac{4}{6}$, ignoring that the pieces are different sizes.
Don't do this:
Do not touch the numerators while the denominators still differ. The pieces are not yet comparable.
The correct way:
Find the LCD first ($6$ here), rewrite $\frac{1}{3}$ as $\frac{2}{6}$, then subtract: $\frac{5}{6} - \frac{2}{6} = \frac{3}{6} = \frac{1}{2}$.
Forgetting to simplify the answer.
Where it slips in:
A student stops at $\frac{3}{6}$ and leaves it, even though it reduces.
Don't do this:
Do not hand in an answer whose numerator and denominator still share a factor.
The correct way:
Check for a common factor and divide it out: $\frac{3}{6} = \frac{1}{2}$. A quick test is whether both numbers are even, or share $3$, $5$, and so on.
Borrowing errors with mixed numbers.
Where it slips in:
Subtracting $3\frac{1}{4} - 1\frac{5}{6}$, a student subtracts $\frac{5}{12}$ from $\frac{3}{12}$ the wrong way round, or forgets to reduce the whole number after borrowing.
Don't do this:
Do not subtract the smaller fraction part from the larger out of order, and do not leave the whole number unchanged after you borrow.
The correct way:
Give the fraction parts the LCD, borrow one whole ($\frac{12}{12}$) when the top fraction is smaller, then subtract: $2\frac{15}{12} - 1\frac{10}{12} = 1\frac{5}{12}$.
Practice Problems On Subtracting Fractions With Unlike Denominators
Work each one through all four steps, then reduce. Answers follow each problem.
$\frac{1}{2} - \frac{1}{3}$.
(Answer: LCD $6$; $\frac{3}{6} - \frac{2}{6} = \frac{1}{6}$.)$\frac{5}{6} - \frac{3}{4}$.
(Answer: LCD $12$; $\frac{10}{12} - \frac{9}{12} = \frac{1}{12}$.)$\frac{7}{10} - \frac{2}{5}$.
(Answer: LCD $10$; $\frac{7}{10} - \frac{4}{10} = \frac{3}{10}$.)$\frac{2}{3} - \frac{1}{6}$.
(Answer: LCD $6$; $\frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$.)$4\frac{1}{3} - 2\frac{3}{4}$.
(Answer: LCD $12$; borrow to get $3\frac{16}{12} - 2\frac{9}{12} = 1\frac{7}{12}$.)Use the shortcut: $\frac{5}{7} - \frac{1}{3}$.
(Answer: $\frac{(5)(3)-(1)(7)}{(7)(3)} = \frac{15-7}{21} = \frac{8}{21}$.)
Where Should You Go Next After Subtracting Fractions With Unlike Denominators?
The common-denominator idea is the gateway to almost everything else in fraction arithmetic, and a few natural doors open from here.
Adding, converting, and comparing fractions, decimals, and percentages. The same equivalent-fraction skill drives addition and every conversion between the three forms.
Improper fractions and mixed numbers. Move fluently between the two so mixed-number subtraction and its borrowing step stop feeling fiddly.
What a numerator really counts. Firming up numerator-and-denominator language removes the most common source of slips.
A live Bhanzu trainer teaches fraction subtraction starting from the "why" (same-size pieces before you subtract) in the Bhanzu algebra program, building the number sense that makes the procedure automatic.
Was this article helpful?
Your feedback helps us write better content