Tan 12 Degrees — Value of tan(12°) and How to Find It

#Trigonometry
TL;DR
The value of tan 12 degrees is approximately $\mathbf{0.2126}$ — it is not a special-angle exact value, so there is no clean surd for it. This article shows how to find $\tan 12°$ honestly (calculator, sine over cosine, the cofunction $\cot 78°$, and interpolation), gives the radian form, and places it on the unit circle.
BT
Bhanzu TeamLast updated on July 16, 20266 min read

The value of tan 12 degrees is approximately $0.2126$ ($0.21255656$ to eight places). Unlike $\tan 30°$ or $\tan 45°$, the angle $12°$ is not a special angle, so $\tan 12°$ has no simple exact surd — it is read from a calculator, a trig table, or rewritten as the cofunction $\cot 78°$.

Quick Answer:

Result: $\tan 12° \approx 0.2126$

In radians: $\tan\left(\frac{\pi}{15}\right) = \tan(0.20944) \approx 0.2126$

Notation: decimal approximation — $0.21255656$ (8 dp)

Method shown: calculator (degree mode), $\tan 12° = \frac{\sin 12°}{\cos 12°}$, the cofunction $\cot 78°$, and table interpolation

Exact form: none simple — $12°$ is not a special angle, so no clean radical exists

Quick Reference — Tangent Near 12 Degrees

Tan 12° sits below the first special landmark $\tan 30°$. The table places it among its small-angle neighbours.

Angle (degrees)

Angle (radians)

$\tan\theta$

Special angle?

$0°$

$0$

$0.0000$

Yes (exact $0$)

$10°$

$\frac{\pi}{18}$

$0.1763$

No

$11°$

$\frac{11\pi}{180}$

$0.1944$

No

$12°$

$\frac{\pi}{15}$

$0.2126$

No — decimal only

$15°$

$\frac{\pi}{12}$

$0.2679$

No (but exact $2-\sqrt3$)

$30°$

$\frac{\pi}{6}$

$0.5774$

Yes ($\tfrac{1}{\sqrt3}$)

The nearest exact landmark above is $\tan 30° = \frac{1}{\sqrt3} \approx 0.5774$, and $\tan 12°$ sits well below it — tangent grows slowly near $0$.

What Does Tan 12 Degrees Mean?

Tangent of an angle is the ratio of sine to cosine: $\tan\theta = \dfrac{\sin\theta}{\cos\theta}$. On the unit circle, that is the $y$-coordinate divided by the $x$-coordinate of the point at angle $\theta$.

A quadrant is one of the four regions the axes cut the plane into, numbered anticlockwise from the top right; $12°$ lands in Quadrant I, where sine and cosine are both positive, so tangent is positive.

Because $12°$ is a shallow angle, the numerator $\sin 12°$ is small while the denominator $\cos 12°$ stays close to $1$, so the ratio is small — about $0.2126$.

How Do You Find the Value of Tan 12 Degrees?

Because $12°$ is not a special angle, there is no surd to simplify to. So how do you find tan 12 degrees without a calculator? You build it from sine and cosine, swap to a cofunction, or interpolate — here are the honest routes.

Method 1: Calculator (set to degree mode)

Type $\tan(12)$ with the calculator in DEG mode.

$$\tan 12° = 0.21255656\ldots \approx 0.2126$$

In radian mode the same keystrokes give $\tan(12\ \text{rad}) \approx -0.636$ — a completely different number, so the mode matters.

Method 2: Sine over cosine

Using $\sin 12° = 0.2079$ and $\cos 12° = 0.9781$:

$$\tan 12° = \frac{\sin 12°}{\cos 12°} = \frac{0.2079}{0.9781} = 0.2126$$

Method 3: Cofunction identity

Tangent and cotangent are cofunctions: $\tan\theta = \cot(90° - \theta)$.

$$\tan 12° = \cot(90° - 12°) = \cot 78° = \frac{1}{\tan 78°}$$

Since $\tan 78° \approx 4.7046$, this gives $\dfrac{1}{4.7046} \approx 0.2126$ — the same value, a third way.

Method 4: Table interpolation

If a trig table lists $\tan 10° = 0.1763$ and $\tan 15° = 0.2679$, estimate $\tan 12°$ by linear interpolation:

$$\tan 12° \approx 0.1763 + \frac{12 - 10}{15 - 10},(0.2679 - 0.1763) = 0.1763 + 0.4(0.0916) = 0.2129$$

That lands within $0.0003$ of the true $0.2126$ — interpolation works well here because tangent is nearly straight near small angles.

What is tan 12 degrees in radians?

The angle converts to $\frac{\pi}{15} \approx 0.2094$ rad, but the value of the tangent is the same number, $\approx 0.2126$. Converting the angle does not change the tangent; it only relabels it.

Examples Using Tan 12 Degrees

Example 1

State $\tan 12°$ to four decimal places.

From a calculator in degree mode, $\tan 12° = 0.2126$.

Example 2 (wrong path first)

Find $\tan 12°$ from $\sin 12°$ and $\cos 12°$.

Wrong attempt. A student divides the larger by the smaller out of habit: $\tan 12° = \dfrac{\cos 12°}{\sin 12°} = \dfrac{0.9781}{0.2079} = 4.705$.

Why it breaks. That flips the ratio — $\tfrac{\cos}{\sin}$ is cotangent, not tangent. The answer $4.705$ is actually $\cot 12°$, which would mean a $78°$ slope, not a shallow $12°$ one.

Correct. $\tan 12° = \dfrac{\sin 12°}{\cos 12°} = \dfrac{0.2079}{0.9781} = 0.2126$.

Example 3

A ramp rises at $12°$. How high is it after a $5$ m horizontal run?

Rise $= 5 \times \tan 12° = 5 \times 0.2126 = 1.063$ m.

Example 4

Compare $\tan 12°$ with $\tan 30°$.

$\tan 12° = 0.2126$; $\tan 30° = 0.5774$. The smaller angle gives a much smaller gradient, as expected near the flat end of the curve.

Example 5

Verify $\tan 12° = \cot 78°$ on a calculator.

$\tan 12° = 0.21256$ and $\cot 78° = \tfrac{1}{\tan 78°} = 0.21256$ — identical, confirming the cofunction identity.

Tan 12 Degrees — Where Students Lose the Mark

Most errors on a small non-special tangent come from a few repeatable habits.

Mistake 1: Flipping the ratio to cotangent

Where it slips in: building tangent from sine and cosine without checking which goes on top.

Don't do this: writing $\tan 12° = \dfrac{\cos 12°}{\sin 12°} = 4.705$.

The correct way: tangent is $\tfrac{\sin\theta}{\cos\theta}$, sine on top. The habit that fixes this is to write "opposite over adjacent" before plugging numbers; the learner who flips it has computed $\cot 12°$ and will report a steep slope for a shallow angle.

Mistake 2: Hunting for an exact surd

Where it slips in: assuming every small angle has a clean value like $\tan 15° = 2 - \sqrt3$.

Don't do this: trying to write $\tan 12°$ as a simple radical.

The correct way: $12°$ is not a special angle, so $\tan 12°$ is given as the decimal $0.2126$. Some nearby angles like $15°$ do have surd forms, but $12°$ does not — the honest answer is the calculator value or a cofunction.

Mistake 3: Forgetting the calculator's angle mode

Where it slips in: the calculator was left in radian mode.

Don't do this: reading $\tan(12) = -0.636$ and reporting it as $\tan 12°$.

The correct way: check DEG mode for $\tan 12°$; $-0.636$ is $\tan(12\ \text{radians})$, an angle of nearly two full turns where tangent can be negative.

Key Takeaways

  • Tan 12 degrees is approximately $0.2126$ — a decimal, not a clean surd.

  • $12°$ is not a special angle, so the value comes from a calculator, $\tfrac{\sin 12°}{\cos 12°}$, the cofunction $\cot 78°$, or interpolation.

  • The value is small because a shallow angle has a small sine over a near-$1$ cosine.

  • In radians the angle is $\frac{\pi}{15}$, but the tangent value stays $\approx 0.2126$.

  • The biggest slip is flipping the ratio and computing $\cot 12°$ instead.

To take tangent values further with a teacher, explore Bhanzu's trigonometry tutor, a high school math tutor, or math classes online.

Practice These Before Moving On

  1. State $\tan 12°$ to four decimal places.

  2. Compute $\tan 12°$ from $\sin 12° = 0.2079$ and $\cos 12° = 0.9781$.

  3. Use $\tan 10° = 0.1763$ and $\tan 15° = 0.2679$ to interpolate $\tan 12°$.

Want a live trainer to walk through more tangent-value problems? Book a free demo class.

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Frequently Asked Questions

What is tan 12 degrees?
Approximately $0.2126$ ($0.21255656$ to eight places). It sits below $\tan 30° = 0.5774$.
Is tan 12 degrees an exact value?
No. $12°$ is not a special angle, so $\tan 12°$ has no simple surd — it is a decimal approximation.
What is tan 12 degrees as a fraction of sine and cosine?
$\tan 12° = \dfrac{\sin 12°}{\cos 12°} = \dfrac{0.2079}{0.9781} = 0.2126$.
What is tan 12 degrees in radians?
The angle is $\frac{\pi}{15} \approx 0.2094$ rad, but the tangent value is unchanged at $\approx 0.2126$.
Is tan 12 degrees positive or negative?
Positive. $12°$ is in the first quadrant, where tangent is positive.
Do I need to memorise tan 12 degrees?
No. Non-special angles like $12°$ are not memorisation targets — you find them with a calculator, sine over cosine, or a trigonometric table.
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