Sin 0 Degrees : Value, Why It Equals 0, and How to Find It

#Trigonometry
TL;DR
The value of sin 0 degrees is exactly 00. This article shows why the sine of a zero angle vanishes using the unit circle and the right triangle, gives a standard-angle table in degrees and radians, and works through examples plus the mistakes students make with 00.
BT
Bhanzu TeamLast updated on August 13, 20266 min read

What Does Sin 0 Degrees Mean?

Sine is one of the three trigonometric ratios - in a right triangle it is the side opposite the angle divided by the hypotenuse. As the angle shrinks toward 0∘0^\circ, the opposite side shrinks toward nothing while the hypotenuse stays, so the ratio heads to 00.

On the unit circle - radius 11, centred at the origin - sine is the yy-coordinate of the point where the angle's radius meets the circle. At 0∘0^\circ that point sits flat on the positive xx-axis at (1,0)(1, 0), so the yy-coordinate, and the sine, is 00.

Where Does Sin 0 Degrees Show Up?

Sine measures the vertical part of a direction, so sin⁡0∘=0\sin 0^\circ = 0 is why a perfectly horizontal push has no upward component at all. A ball rolled flat across a table gains no height, because the launch angle is 0∘0^\circ.

The value also marks every zero crossing of a wave: a sine wave starts at 00, and each time it returns to the axis the angle is a whole multiple of 180∘180^\circ. The pattern is the unit circle sine turning to 00 each time the point crosses the horizontal axis.

Standard-Angle Reference Table

Zero degrees is the starting point of the sine table, where the value is exactly 00. Here are the standard first-quadrant angles in degrees and radians.

Angle (degrees)

Angle (radians)

sin⁡θ\sin\theta (exact)

sin⁡θ\sin\theta (decimal)

0∘0^\circ

00

00

0.00000.0000

30∘30^\circ

π6\dfrac{\pi}{6}

12\dfrac{1}{2}

0.50000.5000

45∘45^\circ

π4\dfrac{\pi}{4}

22\dfrac{\sqrt{2}}{2}

0.70710.7071

60∘60^\circ

π3\dfrac{\pi}{3}

32\dfrac{\sqrt{3}}{2}

0.86600.8660

90∘90^\circ

π2\dfrac{\pi}{2}

11

1.00001.0000

Reading down, sine grows from 00 to 11 as the angle opens - the mirror image of cosine, which shrinks over the same range. Sine and cosine trade places at the ends: sin⁡0∘=0=cos⁡90∘\sin 0^\circ = 0 = \cos 90^\circ.

How Do You Find The Exact Value Of Sin 0 Degrees?

Two views agree that the answer is 00: one reads the unit circle, the other watches the triangle collapse.

Method 1: The unit circle.

Place a point on the unit circle at the angle 0∘0^\circ. No rotation has happened yet, so the point is exactly where the positive xx-axis meets the circle, at (1,0)(1, 0).

Sine is the yy-coordinate:

sin⁡0∘=y-coordinate=0\sin 0^\circ = y\text{-coordinate} = 0

Method 2: The right-triangle view.

Sine is oppositehypotenuse\dfrac{\text{opposite}}{\text{hypotenuse}}. Imagine flattening a right triangle so its angle approaches 0∘0^\circ: the opposite side gets shorter and shorter while the hypotenuse stays fixed.

sin⁡0∘=oppositehypotenuse=0hypotenuse=0\sin 0^\circ = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{0}{\text{hypotenuse}} = 0

Both routes land on the same exact 00. Note this is different from cos 0 degrees, which equals 11 - at 0∘0^\circ sine bottoms out while cosine peaks.

Examples Of Sin 0 Degrees

Example 1

Evaluate 5sin⁡0∘+35\sin 0^\circ + 3.

5sin⁡0∘+3=5×0+3=35\sin 0^\circ + 3 = 5 \times 0 + 3 = 3

Example 2

Simplify cos⁡0∘sin⁡0∘\dfrac{\cos 0^\circ}{\sin 0^\circ} (this is cot⁡0∘\cot 0^\circ). A student writes the answer as 00. What is wrong?

Wrong attempt. Reading sin⁡0∘=0\sin 0^\circ = 0, the student writes cos⁡0∘sin⁡0∘=10=0\dfrac{\cos 0^\circ}{\sin 0^\circ} = \dfrac{1}{0} = 0.

That breaks a basic rule: dividing by 00 does not give 00 — it gives no value at all. Because sin⁡0∘=0\sin 0^\circ = 0 sits in the denominator, the expression is undefined.

Correct. cot⁡0∘=cos⁡0∘sin⁡0∘=10\cot 0^\circ = \dfrac{\cos 0^\circ}{\sin 0^\circ} = \dfrac{1}{0}, which is undefined. Any ratio that divides by sin⁡0∘\sin 0^\circ — cosecant and cotangent at 0∘0^\circ — is undefined.

Example 3

Evaluate sin⁡0∘+sin⁡90∘\sin 0^\circ + \sin 90^\circ.

sin⁡0∘+sin⁡90∘=0+1=1\sin 0^\circ + \sin 90^\circ = 0 + 1 = 1

Example 4

Verify the Pythagorean identity at 0∘0^\circ: show sin⁡20∘+cos⁡20∘=1\sin^2 0^\circ + \cos^2 0^\circ = 1.

02+12=0+1=10^2 + 1^2 = 0 + 1 = 1

The Pythagorean identity holds even at the boundary angle 0∘0^\circ.

Example 5

Show that sin⁡0∘=sin⁡0\sin 0^\circ = \sin 0 in radians.

Converting the angle, 0∘=00^\circ = 0 radians, because 0×π180=00 \times \dfrac{\pi}{180} = 0. So sin⁡0∘\sin 0^\circ and sin⁡0\sin 0 name the same angle, and both equal 00 — the value does not depend on which radian or degree unit you use.

Where Students Trip Up On Sin 0 Degrees

Mistake 1: Treating division by sin 0° as zero

Where it slips in: Evaluating cosecant or cotangent at 0∘0^\circ, where sin⁡0∘\sin 0^\circ lands in the denominator.

Don't do this: Writing csc⁡0∘=1sin⁡0∘=10=0\csc 0^\circ = \dfrac{1}{\sin 0^\circ} = \dfrac{1}{0} = 0. A fraction with 00 on the bottom is undefined, not 00.

The correct way: State that csc⁡0∘\csc 0^\circ and cot⁡0∘\cot 0^\circ are undefined. The first instinct that "zero on the bottom makes the whole thing zero" is the exact habit that produces this error.

Mistake 2: Confusing sin 0° with cos 0°

Where it slips in: Recalling boundary values quickly and swapping the two.

Don't do this: Writing sin⁡0∘=1\sin 0^\circ = 1. That is cos⁡0∘\cos 0^\circ; sine and cosine are opposite at the ends.

The correct way: At 0∘0^\circ the unit-circle point is (1,0)(1, 0) — cosine takes the xx (which is 11), sine takes the yy (which is 00). So sin⁡0∘=0\sin 0^\circ = 0 and cos⁡0∘=1\cos 0^\circ = 1.

Mistake 3: Assuming sin 0° must be "a little more than zero"

Where it slips in: Thinking a real angle can never give an exact 00.

Don't do this: Writing sin⁡0∘≈0.001\sin 0^\circ \approx 0.001 or leaving it as an approximation.

The correct way: sin⁡0∘\sin 0^\circ is exactly 00, not a rounded value. Zero is a genuine, exact output of the sine function.

Key Takeaways

  • Sin 0 degrees equals 00 exactly, because the unit-circle point at 0∘0^\circ is (1,0)(1, 0) and sine is the yy-coordinate.

  • In the right-triangle view, the opposite side shrinks to nothing as the angle goes to 0∘0^\circ, so the ratio is 00.

  • In radians, sin⁡0∘=sin⁡0=0\sin 0^\circ = \sin 0 = 0 — the value does not change with the unit.

  • The main slips are treating division by sin⁡0∘\sin 0^\circ as 00 (it is undefined) and confusing sin⁡0∘\sin 0^\circ with cos⁡0∘=1\cos 0^\circ = 1.

To build these fundamentals with a teacher, explore Bhanzu's trigonometry tutor or high school math tutor sessions, or browse math classes online.

Practice These Before Moving On

  1. Evaluate 7sin⁡0∘+cos⁡0∘7\sin 0^\circ + \cos 0^\circ.

  2. Explain in one line why tan⁡0∘=0\tan 0^\circ = 0 but cot⁡0∘\cot 0^\circ is undefined.

  3. Verify that sin⁡0∘+sin⁡180∘=0\sin 0^\circ + \sin 180^\circ = 0 using the unit circle.

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Frequently Asked Questions

Why is sin 0 degrees equal to 0?
Because at 0∘0^\circ the unit-circle point is (1,0)(1, 0), and sine reads the yy-coordinate, which is 00.
Is sin 0 the same in degrees and radians?
Yes. 0∘0^\circ equals 00 radians, so sin⁡0∘=sin⁡0=0\sin 0^\circ = \sin 0 = 0.
What is cosec 0 degrees?
Undefined. It equals 1sin⁡0∘=10\dfrac{1}{\sin 0^\circ} = \dfrac{1}{0}, and division by 00 has no value.
Is sin 0 degrees exactly 0 or approximately 0?
Exactly 00 - it is not a rounded decimal.
What is the difference between sin 0° and cos 0°?
sin⁡0∘=0\sin 0^\circ = 0 and cos⁡0∘=1\cos 0^\circ = 1; at the zero angle sine bottoms out while cosine peaks.
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